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kotegsom [21]
3 years ago
5

Park A covers an area of 4,926 square kilometers. It is 1,845 square kilometers larger then park B park C is 4,008 square kilome

ters larger then park A What is the area of all parks.
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Mathematics
1 answer:
suter [353]3 years ago
8 0

Answer:

10779

Step-by-step explanation:

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Suzanne needs material for her school project. She buys 4.75 yards of material at $5.37 a yard. What is the total cost of the ma
vovangra [49]
The material costs 5.37 for 1 yard.

 Multiply the cost of 1 yard by the number of yards bought:

5.37 per yard x 4.75 yards = $25.51 Total cost.

The answer would be D.
3 0
3 years ago
Idk the answer to this question please help me
erica [24]
2/3 x 42/3
hope this helps

7 0
3 years ago
1. The current ratio (assets/liabilities) of company X is 3.1. Given that the current assets are $186000, find the current liabi
katrin [286]
<span>1. The current ratio (assets/liabilities) of company X is 3.1. Given that the current assets are $186000, find the current liabilities:

Assets = A
Liabilities = L

A / L = 3.1 => L = A / 3.1

A =  186000 => L = 18600 / 3.1 = 6000

Answer: $ 6000

2. The board of directors determines that the current ratio must never be below 2.6. What is the maximum amount that the company can borrow?


A/L ≥ 2.6

=> L ≤ A / 2.6

=> L ≤ 186000 / 2.6

L ≤ 71538.46

Answer: $71538.46
</span>
6 0
3 years ago
Georgie joins a gym. She pays $25 to sign up and then $15 each monthLabel the y-intercept, the slope, and your axes.
Degger [83]
The first thing you should do for this case is to find the equation of the line that best suits the problem and then plot it.

Let X: number of months and: amount paid.

The equation of the line is
y = 15x + 25 y-intercept = 25

the slope = 15

Answer:

Georgie pays (y axis) $ 15 dollars (the spole) monthly (x-axis) in the gym with a $ 25 registration (y -intercept)
7 0
3 years ago
Can you please help with this question about exponential equations?
RSB [31]

Since t represents the number of years passed since 2005, in 2005 we have t=0, and in 2015 we have t=10. Let P_J(y),P_D(y) represent the profits of Jones and Davis, respectively, at year y.

We have

P_J(2005) = 10(0.99)^0 = 10,\quad P_J(2015) = 10(0.99)^{10}\approx 9

P_D(2005) = 8(1.01)^0 = 8,\quad P_D(2015) = 8(1.01)^{10}\approx 9

Choosing the best company somehow depends on how much time you can wait: Jones start with a higher value (10 vs 8), but it has a descending trend, because the multiplicative factor 0.99^t goes to zero as t grows.

On the other hand, Davis starts with a smaller value, but 1.01^t tends to infinity as t grows.

So, if you need an immediate result, the most valuable company is Jones, otherwise you're certain can Davis will eventually become bigger.

More precisely, we have

8\cdot 1.01^t = 10\cdot 0.99^t \iff 0.8 = \left(\dfrac{0.99}{1.01}\right)^t \iff t\approx 11

So, after 11 years, Davis will overcome Jones.

3 0
3 years ago
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