Answer:
Q1: p = - 33
Q2: d = - 99
Q3: t = - 13
Step-by-step explanation:
Q1:
We solve this taking LCM.
We get:
Q4:
Again we proceed like Q1 by taking LCM.
We get:
Q7: 5t + 12 = 4t - 1
We club the like terms on either side.
Hence, the answer.
A=2 b=2 c=1 Find the value of 2abcosC
1 answer:
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Answer:
The given line segment whose end points are A(2,2) and B(3,8).
Distance AB is given by distance formula , which is
if we have to find distance between two points (a,b) and (p,q) is
=
AB= = 6.08 (approx)
Line segment AB is dilated by a factor of 3.5 to get New line segment CD.
Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)
Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)
CD = AB × 3.5
CD = √37× 3.5
= 6.08 × 3.5
= 21.28 unit(approx)
2. Slope of line joining two points (p,q) and (a,b) is given by
m=
m=
As the two lines are coincident , so their slopes are equal.
Slope of line AB=Slope of line CD = 6
Answer:
The sum of the given series is 1023
Step-by-step explanation:
Geometric series states that a series in which a constant ratio is obtained by multiplying the previous term.
Sum of the geometric series is given by:
where a is the first term and n is the number of term.
Given the series:
This is a geometric series with common ratio(r) = 2
We have to find the sum of the series for 10th term.
⇒ n = 10 and a = 1
then;
Therefore, the sum of the given series is 1023