We have that
the point J (10,-6)
the rule is-----------(x,y)-------------------> (x-3, y-2)
therefore
J (10,-6)----------------- > (10-3,-6-2)--------> (7,-8)
the answer is
<span>the y-coordinate of J” is -8</span>
Answer:
Range is : { -10, -7, -5, -2 }
Step-by-step explanation:
Given:
The function is given as:

The domain of the function = { -3, 0, 2, 5 }
A function's input is called its domain and a function's output is called its range.
The range depends on the domain values. So, the values of 'y' are the values of range and the values of 'x' are the values of domain.
Here, the domain is given as:
Domain = { -3, 0, 2, 5 }
We need to find the values of 'y' for each value of 'x' taken from the domain set.
Plug in
. This gives,

Plug in
. This gives,

Plug in
. This gives,

Plug in
. This gives,

Therefore, the set of all values of 'y' is the range.
Range is equal to { -10, -7, -5, -2 }.
Answer: The answer is B
Step-by-step explanation: 122 >7 (z+8) -5 (6+z). Then switch them, 7 (z+8) -5 (6+z) <122. Expanded: 7 (z+8) -5 (6+z) <122:v 2z+26
2z+26<122, subtract 26 from both sides: 2z+26-26<122-26
Simplify: 2z<96, divide both sides by 2: 2z over 2 < 96 over 2
and finally simplified: Z<48
HOPE THIS HELPED YOU OUT!
IF NOT SORRY!
Answer:
By hypotenuse - side test (HL) the two triangles are congruent.
Step-by-step explanation:
In ∆ABC and ∆DCB
i) angleABC = angleDCB.....(each 90°)
ii) BC = BC .....( common side)
iii) AC = DB.....(given)
therefore by hypo-side test ∆ABC congruent ∆DCB