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3 years ago

Look at the figure below:

Mathematics

2 answers:

quester [9]3 years ago

8 0

Answer:

cos y° = b divided by 6

Step-by-step explanation:

Trigonometric ratios :

$Sin \theta = \frac{Perpendicular}{Hypotenuse}$

We are given that sin y° = a divided by 6

$sin y^{\circ}=\frac{a}{6}$

On comparing

Perpendicular = a

Hypotenuse = 6

$Tan \theta= \frac{Perpendicular}{Base}$

tan y°=a divided by b

On comparing

Perpendicular = a

Base = b

So, $cos \theta = \frac{Base}{Hypotenuse}$

$Cos y^{\circ}=\frac{b}{6}$

So, Option d is true

cos y° = b divided by 6

Digiron [165]3 years ago

8 0

Answer:

cos y° = b divided by 6

Step-by-step explanation:

i took the test a got it right

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Debit cards and credit cards are used in various ways. Determine how the two cards are alike or different. Use the 10 statement

elixir [45]

Answer:

Credit cards- 1,4,5,8

Debit cards- 2,9,6

Both- 3,10,7

I think its right but i'm not sure

3 0

3 years ago

A university wants to compare out-of-state applicants' mean SAT math scores (?1) to in-state applicants' mean SAT math scores (?

nordsb [41]

Answer:

d. Yes, because the confidence interval does not contain zero.

Step-by-step explanation:

We are given that the university looks at 35 in-state applicants and 35 out-of-state applicants. The mean SAT math score for in-state applicants was 540, with a standard deviation of 20.

The mean SAT math score for out-of-state applicants was 555, with a standard deviation of 25.

Firstly, the Pivotal quantity for 95% confidence interval for the difference between the population means is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t__n__1-_n__2-2$

where, $\bar X_1$ = sample mean SAT math score for in-state applicants = 540

$\bar X_2$ = sample mean SAT math score for out-of-state applicants = 555

$s_1$ = sample standard deviation for in-state applicants = 20

$s_2$ = sample standard deviation for out-of-state applicants = 25

$n_1$ = sample of in-state applicants = 35

$n_2$ = sample of out-of-state applicants = 35

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(35-1)\times 20^{2} +(35-1)\times 25^{2} }{35+35-2} }$ = 22.64

<em>Here for constructing 95% confidence interval we have used Two-sample t test statistics.</em>

So, 95% confidence interval for the difference between population means ( $\mu_1-\mu_2$ ) is ;

P(-1.997 < $t_6_8$ < 1.997) = 0.95 {As the critical value of t at 68 degree

of freedom are -1.997 & 1.997 with P = 2.5%}

P(-1.997 < $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 1.997) = 0.95

P( $-1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ${(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}$ < $1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.95

P( $(\bar X_1-\bar X_2)-1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.95

<u>95% confidence interval for</u> ( $\mu_1-\mu_2$ ) =

[ $(\bar X_1-\bar X_2)-1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ]

=[ $(540-555)-1.997 \times {22.64 \times \sqrt{\frac{1}{35} +\frac{1}{35} } }$ , $(540-555)+1.997 \times {22.64 \times \sqrt{\frac{1}{35} +\frac{1}{35} } }$ ]

= [-25.81 , -4.19]

Therefore, 95% confidence interval for the difference between population means SAT math score for in-state and out-of-state applicants is [-25.81 , -4.19].

This means that the mean SAT math scores for in-state students and out-of-state students differ because the confidence interval does not contain zero.

So, option d is correct as Yes, because the confidence interval does not contain zero.

6 0

3 years ago

Solve the equation 9b2 + 30b + 25 = 0.

jeka57 [31]

Factor the equation into...
(3b+5)(3b+5)=0
Each factor 3b+5=0 so 3b=-5 so b=-5/3

Check:
9(-5/3)^2+30(-5/3)+25=
9(25/9)-50+25=
25-50+25=0
It checks,

So answer is A.-5/3

5 0

2 years ago

Please help!! I'm super confused

harkovskaia [24]

<h3>Answer: 126.5 square cm</h3>

===================================================

Explanation:

Check out the diagram below. I've drawn a horizontal line to split the orange region into two parts: a triangle on top and a rectangle down below.

The triangle has base 11 cm and height 7 cm. The area is base*height/2 = 11*7/2 = 77/2 = 38.5 sq cm.

The rectangle has area 11*8 = 88 sq cm.

The total area of the entire orange figure is 38.5+88 = 126.5 square cm

4 0

3 years ago

The equation y = 1 5 x represents a proportional relationship. Explain how you can tell the relationship is proportional from th

Vesna [10]

Answer:

Step-by-step explanation:

"y = 1 5 x" is ambiguous; please do not leave spaces. I'm assuming you meant y = 15x.

If you graph this, you'll see a line with slope 15 that goes through the origin. If there were a y-intercept other than zero, such as in y = 15x + 5, this equation would not represent a proportional relationship.

In summary:

There's a constant ("constant of proportionality") slope, which here is 15.

The line MUST go through the origin.

5 0

3 years ago

Read 2 more answers