The expression for the perimeter of the rectangle is 2(11c - 11d)
Perimeter of a rectangle = 2(length + width)
Length = 3c - 9d
Length = 3c - 9d Width = 8c - 2d
The expression for the perimeter can be expressed thus :
2(3c - 9d + 8c - 2d)
Collect like terms :
2(3c + 8c - 9d - 2d)
2(11c - 11d)
Hence, the expression for the perimeter of the rectangle is 2(11c - 11d)
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Answer:
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Step-by-step explanation:
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<u>Answer</u><u>:</u><u> </u><u>The</u><u> </u><u>correct </u><u>answer</u><u> </u><u>is</u><u> </u><u>B</u><u>.</u>
<span>Standard Form of an Equation of an Hyperbola opening up and down is:
(y-k)^2 / b^2 - (x-h)^2 / a^2 = 1
</span><span>where Pt(h,k) is a center with vertices 'b' units up and down from center.
</span><span>vertices: vertices: (0,+-2) b = 2 AND Center is (0,-0)
(y)^2/4-(x)^2/a^2=1
</span><span>foci: (0,+-7)
a^2 = 24
square root of 4 + a^2 = 5.29
4 + 5.29 = 9.29
y^2 / 4 - x^2 / 24 = 1</span>
