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Lorico [155]
3 years ago
12

if the temperature dcreases by a constant rate of 3 degrees celcius each minute what will the temperature cecius after 5 minute

Mathematics
2 answers:
Naily [24]3 years ago
6 0

Hello friends,

Let x represent the start temperature.

Start with finding the total drop in temperature, 3 * 5 = 15.

Then subtract from the starting temperature, x - 15.

Final answer, x - 15.

Hope I helped :)

kozerog [31]3 years ago
5 0

Answer:

i realy dont known dude haaaaaaaahaaahahahah

Step-by-step explanation:

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2times 5 to the power of 2
Bumek [7]
You do 2(5)^2 and the answer is 50

3 0
3 years ago
The number of requests for assistance received by a towing service is a Poisson process with rate θ = 4 per hour.a. Compute the
aliya0001 [1]

Answer:

a) 9.93% probability that exactly ten requests are received during a particular 2-hour period

b) 13.53% probability that they do not miss any calls for assistance

c) 2

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Poisson process with rate θ = 4 per hour.

This means that \mu = 4n, in which n is the number of hours.

a. Compute the probability that exactly ten requests are received during a particular 2-hour period.

n = 2, so \mu = 4*2 = 8

This is P(X = 10). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-8}*8^{10}}{(10)!} = 0.0993

9.93% probability that exactly ten requests are received during a particular 2-hour period

b. If the operators of the towing service take a 30-min break for lunch, what is the probability that they do not miss any calls for assistance?

n = 0.5, so \mu = 4*0.5 = 2

This is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

13.53% probability that they do not miss any calls for assistance

c. How many calls would you expect during their break?

n = 0.5, so \mu = 4*0.5 = 2

4 0
3 years ago
Write the function in vertex form. y=-x^2-8x-9
xeze [42]

Answer:

y = -(x+4)² +7

Step-by-step explanation:

I find it convenient to factor the leading minus sign from the first two terms, then work with what's left.

... y = -(x² +8x) -9

Now, add the square of half the x-coefficient inside parentheses. Add the opposite of that amount outside parentheses.

... y = -(x² +8x +4²) -9 +4²

... y = -(x +4)² +7 . . . . . . . . . rewrite parentheses as a square; collect terms

4 0
3 years ago
Identify the slope and y-intercept of the line x + 3y = -18.
Dmitry [639]

Answer:

Slope: -1/3

Y-intercept: -6

Step-by-step explanation:

x + 3y = -18

x+18 = 3y

-3y/-3 = x/-3+18/-3

y = -1/3x - 6

6 0
3 years ago
Please help me <br> i'll mark u as brainiest if u get it right
Black_prince [1.1K]

Answer: a) 46 minutes
               
b) 10:47

The basic knowledge for this is that 60 minutes = 1 hour

<u>a)</u> Question a asks for how long it took from a 10:34 bus from Mosley to reach Bamford. From the table you can see that the 10:34 bus reaches Bamford at 11:20. All you have to do is count from 10:34 to 11:20.
10:34 will become 11:00 at 10:60 right? Clock's generally don't show 10:60 but goes directly to 11:00 after 1 minute is passed at 10:59. So from 10:34 to 11:00, it takes 26 minutes. Remember the bus reaches at 11:20 so from 11:00 to 11:20, it takes 20 minutes. Now add them up:
26 minutes + 20 minutes = 46 minutes

Here you go! Total 46 minutes from Mosley to Bamford.

<u>b)</u> From question b, we can see that Trina did not ride the first bus or by any chance missed it because the bus left at 10:14 and she is at the station at 10:15. Now think it from your perspective! You missed the first bus and you are in a big rush. So to reach your destination as early as possible, you will obviously take the next earliest bus. The next bus is at 10:24 (Belton). So if we take the 10:24 bus in Belton, it reaches at 10:47 in Garton.


 ∩_∩
(„• ֊ •„)♡
┏━∪∪━━━━┓
   hope it helped
┗━━━━━━━┛

4 0
2 years ago
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