Answer:
Answers are in bold type
Step-by-step explanation:
f(x) = 
The parabola opens up, so has a minimum at the vertex.
Let (h, k) be the vertex
h = -b/2a = - (-144)/2(1) = 57
k = 57^2 - 144(57) = 3249 - 6498 = -3249
Therefore, the vertex is (57, -3249)
The minimum value is -3249
The domain is the set of real numbers.
The range = {y | y ≥ -3249}
The function decreases when -∞ < x < 57 and increases when 57 > x > ∞
The x - intercepts: = 0
x(x - 114x) = 0
x = 0 or x = 114
x-intercepts are (0, 0) and (0, 114)
When x = 0, then we get the y-intercept. So, 0^2 - 114(0) = 0
y-intercept is (0, 0)
First option is correct.
Since we have given that
JKL is a right triangle.
Length of JK = 12
Length of KL = 5
By Pythagoras theorem, we get that
So, cos (L) would be
cos(L)=base/hypotenuse
cos(L)=5/13
Hence, First option is correct.
learn more about Pythagoras theorem and cosine ratios here:
brainly.com/question/9027282
#SPJ1
29 mg = 0.029 g hope this helps
<u>Answer:</u>
c= -1/2
<u>Step-by-step explanation:</u>
Let's solve your equation step-by-step.
4
/3 = −6c −
5/
3
Step 1: Simplify both sides of the equation.
4
/3 =−6c + −5
/3
Step 2: Flip the equation.
−6c + −5
/3 = 4/3
Step 3: Add 5/3 to both sides.
−6c + −5
/3 + 5
/3 = 4/3 + 5
/3 −6c
=3
Step 4: Divide both sides by -6.
−6c −6 = 3
− 6
c = −1
/2
N=-1 distribute then isolate your variable and divide
