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masha68 [24]
3 years ago
6

Find the midpoint between the two points. A(2,-1) and B(-6,0)!! Pleaseee

Mathematics
1 answer:
Illusion [34]3 years ago
5 0

Answer:

hope it helps you .......

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What is an equation of the line that passing through the points (-2, -5) and (4, 7) ?
monitta

Answer:

y=2x-1

Step-by-step explanation:

Use the slope-intercept formula: y=mx+b where m is slope and b the y-intercept.

(-2,-5)(4,7)

Use the slope formula for when you have two points:

\frac{y(2)-y(1)}{x(2)-x(1)}=\frac{rise}{run}

Rise over run is the change in the y-axis over the change in the x-axis. Insert values:

\frac{7-(-5)}{4-(-2)}

Simplify parentheses (negative+negative=positive)

\frac{7+5}{4+2}

Simplify

\frac{12}{6}=2

2 is the slope:

y=2x+b

Now use one of the points to find the y-intercept by substituting the x and y values into the equation. Solve for b:

(4,7)

y=2x+b\\7=2(4)+b

7=8+b\\7-8=8-8+b\\7-8=b\\-1=b\\b=-1

The y-intercept is -1. Insert into the equation. Change the + symbol to -:

y=2x-1

Done.

6 0
3 years ago
An ancient Chinese candle clock tells the amount of time that has passed by the amount of wax that has been melted off the candl
rjkz [21]
Two candles=8 hours=8*60=480 minutes
4 inch is 4/12 of a candle, 4/12 of 4 hours=16/12=4/3 hours=80 minutes
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8 0
3 years ago
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Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-6, 1); focus: (-6, 0)
GREYUIT [131]

Answer: (x+6)^2=-4(y-1)

Step-by-step explanation:

Given

Vertex of the parabola (-6,1)

Focus of the parabola (-6,0)

As the x coordinate of vertex and focus is same and focus lie below the vertex, therefore the parabola is the type of

(x+6)^2=-4a(y-1)

distance between Vertex and focus is 1 unit

\therefore a=1

Parabola becomes

\Rightarrow (x+6)^2=-4(y-1)

8 0
3 years ago
Please helppp<br> a. what's the domain of c
snow_tiger [21]

Answer:

5

Step-by-step explanation:

4 0
2 years ago
45 POINTS
vladimir1956 [14]

Answer:The minunum quality of the beries is 7

3 0
3 years ago
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