Answer:
![(-\infty, -5] \cup (4,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20-5%5D%20%5Ccup%20%284%2C%5Cinfty%29)
Step-by-step explanation:
The symbol
is set notation for UNION--put two sets together into one set.
The first part of the interval notation describes x less than or equal to -5 -- notice the bracket symbol after -5, meaning include -5.
Answer:
12%
12% of Jill's movies are comedies.
Step-by-step explanation:
24/200 x 100/1= 12%
A chord is a line segment that connects any two points on a circle.
Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9
We have to find the probability that in a randomly selected week the number of burglaries is at least three.
P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........
= 1 - P(X < 3)
= 1 - [ P(X=2) + P(X=1) + P(X=0)]
The Poisson probability at X=k is given by
P(X=k) = 
Using this formula probability of X=2,1,0 with mean = 1.9 is
P(X=2) = 
P(X=2) = 
P(X=2) = 0.2698
P(X=1) = 
P(X=1) = 
P(X=1) = 0.2841
P(X=0) = 
P(X=0) = 
P(X=0) = 0.1495
The probability that at least three will become
P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]
= 1 - [0.2698 + 0.2841 + 0.1495]
= 1 - 0.7034
P(X ≥ 3 ) = 0.2966
The probability that in a randomly selected week the number of burglaries is at least three is 0.2966