Answer:
Pretty sure it's 27
Step-by-step explanation:
(2 4= 8) + 3 (4 4= 16)=27
Answer:
Step-by-step explanation:
Given
The dimension of the box is
Space occupied by the box is equal to its volume i.e.
The volume of the box is .
Answer:
A rectangle is defined by its length = L, and its width = W.
So the perimeter of the of the rectangle can be written as:
Perimeter = 2*L + 2*W.
In this case, we want to leave the perimeter fixed, so we have:
24ft = 2*L + 2*W.
Now, we do not have any other restrictions, so to know the different dimensions now we can write this as a function, by isolating one of the variables.
2*L = 24ft - 2*W
L = 12ft - W.
or:
L(W) = 12ft - W.
Such that:
W must be greater than zero (because we can not have negative or zero width).
And W must be smaller than 12ft (because in that case we would have zero or negative length)
Then the possible different dimensions are given by:
L(W) = 12ft - W
0ft < W < 12ft.
<span> <u>24 + 3x = 3x + 3(7 - 1)</u>
Eliminate the parentheses: 24 + 3x = 3x + 3(6)
24 + 3x = 3x + 18
Subtract 3x from each side: <em>24 = 18</em>
Look at that for a second. Can ANY value of 'x' make 24 equal to 18 ?
I don't think so.
There's NO number that makes the equation a true statement.
That's just another way to say: "The equation has NO solution."</span>
This question wants you to find a common denominator for the fractions.
This means finding the LCM, least common multiple, for 21 and 9.
This can be done by listing the multiples for each number until they meet at a common one.
9:
9
18
27
36
45
54
63
21:
21
42
63
This means the LCM of 21 and 9 is 63.
So the lowest possible common denominator is 63.
21 • 3 = 63
So you have to multiply the numerator of 2/21 by 3 as well.
2 • 3 = 6
2/21 = 6/63
Now do the same for 1/9.
9 • 7 = 63
Multiply the numerator, 1, by 7.
1 • 7 = 7
1/9 = 7/63
So in the first blanks, you would put 6/63 for what 2/21 is equal to and 7/63 for what 1/9 is equal to.
7/63 is greater than 6/63.
7/63 > 6/63
That means 1/9 > 2/21
So 2/21 < 1/9 is the answer to the last blank.
Hope this helps!