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mixer [17]
3 years ago
13

Joan adopt two kittens snowflake has a mass of 2 kg and midnight has a mass of 997 g what is the difference between the masses o

f the kittens gram
Mathematics
1 answer:
exis [7]3 years ago
7 0

Answer:

Given,

mass of snow flake = 2 kg

mass of midnight = 997 gm

Now,

1 kg = 1000 gm

2 kg = 1000 * 2

= 2000 gm

therefore the difference between the masses of the kittens = 2000

- 997

= 1003 gm (is the answer)

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Thirty-five sophomores, 69 juniors and 24 seniors are randomly selected from 461 sophomores, 328 juniors and 558 seniors at a ce
LekaFEV [45]

Answer:

Stratified sampling technique(A)

Step-by-step explanation:

From the question, the population of an high school from which selection was made equals 461 sophomores, 328 juniors and 558 seniors.

35 sophomores, 69 juniors and 24 seniors are randomly selected. The technique used in selecting is Stratified sampling technique. This is because stratified sampling involves dividing the entire population into stratas and then selects a final sample randomly from the different strata. This means that a smaller part of the entire population is used as a sample in drawing conclusions for the entire population.

7 0
3 years ago
During gym class, Alexis played dodgeball for 34 hour.
IRISSAK [1]

the soultion in 20

Step-by-step explanation:

first get the 34 hour of dogeball and get the 14 hour of basketball subtract 34 - 14 first 4 - 4 = 0 then 30 - 10 = 20

6 0
2 years ago
Read 2 more answers
Perimeter of an isosceles triangle is 90 m. If the length of the two equal sides is three fourth of the unequal side , find the
Sveta_85 [38]

Answer:

The length of the equal side is 27 meters each and that of the unequal side is 36 meters

Step-by-step explanation:

An isosceles triangle is a triangle with two sides being equal (also two equal base angles).

Let us assume the length of the two equal sides to be x meters each, and the length of the unequal side to be y meter. Since the perimeter of the triangle is 90 m, it can be expressed as:

x + x + y = 90

2x + y = 90

But the length of the equal side is  three fourth of the unequal side, i.e x = 3/4y

Therefore:

2(3/4y) + y = 90

3/2y + y = 90

2.5y = 90

y = 90/2.5

y = 36 meters

Also x = 3/4 * 36 = 27 meters

The length of the equal side is 27 meters each and that of the unequal side is 36 meters

5 0
3 years ago
1) Determine the discriminant of the 2nd degree equation below:
Aleksandr-060686 [28]

\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}

We have, Discriminant formula for finding roots:

\large{ \boxed{ \rm{x =  \frac{  - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

Here,

  • x is the root of the equation.
  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5\pm  \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5  \pm  \sqrt{25 - 24} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5 \pm 1}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 2 \: or  - 3}}}

❒ p(x) = x^2 + 2x + 1 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{  - 2 \pm  \sqrt{ {2}^{2}  - 4 \times 1 \times 1} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm 0}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 1 \: or \:  - 1}}}

❒ p(x) = x^2 - x - 20 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - ( - 1) \pm  \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{1 \pm 9}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \:  - 4}}}

❒ p(x) = x^2 - 3x - 4 = 0

\large{ \rm{ \longrightarrow \: x =   \dfrac{  - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3 \pm \sqrt{9  + 16} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3  \pm 5}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \:  - 1}}}

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
3 years ago
Read 2 more answers
How much is a 15 percent down payment on a purchase of 205,000
insens350 [35]
Change 15% into a decimal

15% = 15/100 = 0.15

multiply 0.15 and 205,000 together

205000 x 0.15 = <span>30750

$30,750 is your answer

hope this helps</span>
6 0
3 years ago
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