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alina1380 [7]
4 years ago
10

Work out the following questions ​

Mathematics
2 answers:
Schach [20]4 years ago
7 0

Answer:

as follow

Step-by-step explanation:

a

\frac{2}{7}  \div  \frac{3}{4}  =  \frac{2}{7}  \times  \frac{4}{3}  =  \frac{8}{21}

b

\frac{5}{9}  \div  \frac{5}{1}  =  \frac{5}{9}  \times  \frac{1}{5}  =  \frac{1}{9}

Klio2033 [76]4 years ago
4 0

Step 1. Turn the second fraction (the one you want to divide by) upside down

(this is now a reciprocal).

Step 2. Multiply the first fraction by that reciprocal

Step 3. Simplify the fraction (if needed)

Example:

1/2  ÷   1/6

Step 1. Turn the second fraction upside down (it becomes a reciprocal):

1/6 becomes  6/1

Step 2. Multiply the first fraction by that reciprocal:

(multiply tops ...)

1/2 ×  6/1  =   1 × 6/2 × 1  =   6/2

(... multiply bottoms)

 

Step 3. Simplify the fraction:

6/2  =  3

This is how you divide fractions. Now try it your self!

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Which fraction is less than 1 chose all of the correct answer, and explain why you chose and write it down and explain your answ
EleoNora [17]

Answer:

(3/4) and (2/3).

Step-by-step explanation:

For a fraction of the form (p / q), the number in front of the division (p) is the numerator. The number after the division (q) is the denominator.

\begin{aligned} \frac{p}{q} \quad \genfrac{}{}{0}{}{(\text{numerator})}{(\text{denominator})}\end{aligned}.

A positive fraction (p/q) (p,\, q > 0) is less than 1 as long as the numerator p is smaller than the denominator q (that is, p < q.) The reason is that as long as p,\, q > 0:

\begin{aligned} & \frac{p}{q} < 1 \\ \iff & (q)\, \left(\frac{p}{q}\right) < (q)\, (1) && (\text{given that $q > 0$}) \\ \iff & p < q\end{aligned}.

For example, in the fraction (2/3), 2 is the numerator while 3 is the denominator. Both the numerator and the denominator are positive, while the numerator 2\! is smaller than the denominator 3\!. Therefore, (2/3) would be less than 1.

6 0
1 year ago
509 to nearest hundreds​
vladimir1956 [14]
509 rounded to the nearest hundred would be 500
6 0
4 years ago
Read 2 more answers
(1Q) Find a function for the graph below
anzhelika [568]

ANSWER

C.

f(t) =  - 3 \sin(3t)

EXPLANATION

The given function has range:

-3≤f(t)≤3

This implies that, the amplitude is

|a|  = 3

The function is symmetric with respect to the origin so this is a sine function.

This function is again reflected in the x-axis, hence

a=-3.

The period of this function is

\frac{2\pi}{b}  = \frac{2\pi}{3}

This implies that, b=3,

hence the equation of the function is

f(t) =  - 3 \sin(3t)

3 0
3 years ago
PLEASE HELP ASAP!!!!!
Wittaler [7]

Answer:

sec(x)

Step-by-step explanation:

cos(x)+cos(x)tan^2(x)

Multiply cos(x) by 1:

cos(x)*1+cos(x)tan^2(x)

Factor out cos(x):

cos(x)(tan^2(x)+1)

Apply the pythagorean identity (tan^2(x)+1=sec^2(x)):

cos(x)sec^2(x)

Rewrite sec^2(x):

cos(x)(\frac{1}{cos(x)})^2 \\cos(x)\frac{1}{cos^2(x)}

Cancel cos(x):

\frac{1}{cos(x)}

Rewrite:

sec(x)

5 0
4 years ago
WILL mark BRAINLIEST <br> WHICH OF THE FOLLOWING COULD BE THE EQUATION OF THE FUNCTION BELOW?
AysviL [449]

Answer:

y = 0.5cos(4(x+π/2)) -2

Step-by-step explanation:

The centerline of the oscillation is at -2, so only the 2nd and 4th choices are viable.

The multiplier of x is computed from (2π)/period. One period is π/2, so the multiplier of x is ...

... 2π/(π/2) = 4 . . . . . matching the 2nd selection.

The horizontal offset in the second equation (π/2) is of no consequence, as it is one full period of the function.

The peak-to-peak amplitude of the oscillation is 1 unit, so the multiplier of the cosine function (which usually has a peak-to-peak value of 2 units) is 0.5. Every offered answer has that characteristic.

The appropriate choice is the 2nd one:

... y = 0.5cos(4(x+π/2)) -2

3 0
3 years ago
Read 2 more answers
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