Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
The answer to question above is 0.0000593
9x-8=9x-3/2 X3
9x-8=27x-9/2
2(9x-2)=27x-9
18x-4 =27x-9
18x-27x=-9+4
-9x =-5
9x=5
X=5/9 answer
Answer:
11 pages with picture to every nine pages without pictures. or 11 per every 9
Step-by-step explanation:
divide each number by a common denominator, in this case 5, to get a change from 55 per every 45 to 11 per every 9.
Answer:
* * *
|-4|___|-3|___|-2|___|-1|___|0|___|1|___|2|___|3|___|4|___|5|___|6|
Step-by-step explanation:
You are looking for a dot over -2 (that is 2 units to the left of 0).
You are looking for a dot over 3 (that is 3 units to the right of 0).
You are looking for a dot over 4 (that is 4 units to the right of 0).
If you find one of the graphs matches this, then you should select.
The graph would look like this:
* * *
|-4|___|-3|___|-2|___|-1|___|0|___|1|___|2|___|3|___|4|___|5|___|6|
