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marissa [1.9K]
3 years ago
5

WHAT IS THE STANDARD FORM OF 5.93e-5?

Mathematics
1 answer:
Valentin [98]3 years ago
3 0
The answer to question above is 0.0000593
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A sample is selected from a population with μ = 46, and a treatment is administered to the sample. After treatment, the sample m
Georgia [21]

Answer:

0.5

Step-by-step explanation:

Solution:-

- The sample mean before treatment, μ1 = 46  

- The sample mean  after treatment, μ2 = 48

- The sample standard deviation σ = √16 = 4

- For the independent samples T-test, Cohen's d is determined by calculating the mean difference between your two groups, and then dividing the result by the pooled standard deviation.

                           Cohen's d = \frac{u2 - u1}{sd_p_o_o_l_e_d}

- Where, the pooled standard deviation (sd_pooled) is calculated using the formula:

                          sd_p_o_o_l_e_d =\sqrt{\frac{SD_1^2 +SD_2^2}{2} }

- Assuming that population standard deviation and sample standard deviation are same:

                          SD_1 = SD_2 =  σ = 4

- Then,

                           sd_p_o_o_l_e_d =\sqrt{\frac{4^2 +4^2}{2} } = 4

- The cohen's d can now be evaliated:

                          Cohen's d = \frac{48 - 46}{4} = 0.5

6 0
2 years ago
If using the method of completing the square to solve the quadratic equation
oee [108]
The answer would be 361/4 added to each side of the formula
7 0
2 years ago
Solve the equation f(x)=2x+7 ​
bija089 [108]

Answer:

2

Step-by-step explanation:

6 0
3 years ago
There are 752 cal in 8 ounces of a certain ice cream how many calories are there in 2 pounds
Irina18 [472]
So, 8 ounces is equivalent to .5 pounds. Therefore, 32 ounces is equivalent to 2 pounds. Or, there are 4 8ounce measurements to get to 2 pounds.

752 calories * 4 = 3008 calories in 2 pounds of ice cream.
4 0
2 years ago
WILL GIVE BRAINLIEST, PLEASE HELP ASAP!!! MY LIFE DEPENDS ON THIS!!!
ahrayia [7]

h(x) = 3 * (2)^x

Section A is from x = 1 to x = 2

h(1) = 3 * (2)^1 = 3 * 2 = 6

h(2) = 3 * (2)^2 = 3 * 4 = 12

so

the average rate of change  = (12 - 6)/(2 - 1) = 6


Section B is from x = 3 to x = 4

h(3) = 3 * (2)^3 = 3 * 8 = 24

h(4) = 3 * (2)^4 = 3 * 16 = 48

so

the average rate of change  = (48 - 24)/(4 - 3) = 24


Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

the average rate of change of section B is 24 and the average rate of change of section A is 6

So 24/6 = 4

The average rate of change of Section B is 4 times greater than the average rate of change of Section A

It's exponential function, not a linear function; so the rate of change is increasing.

7 0
2 years ago
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