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klasskru [66]
4 years ago
6

10 < 0.25 ( x + 1 ) < 11

Mathematics
1 answer:
AURORKA [14]4 years ago
6 0
10 <0.25 (x + 1) <11
 
We must solve two inequalities in this case.
 Inequality 1:
 
10 <0.25 (x + 1)
 10 / 0.25 <x + 1
 40 <x + 1
 40-1 <x
 39 <x
 Inequality 2:
 
0.25 (x + 1) <11
 (x + 1) <11 / 0.25
 (x + 1) <44
 x <44-1
 x <43
 The final result is:
 39 <x <43
 Answer:
 
39 <x <43
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Volumes of the solids with disk or shell method?
lina2011 [118]

The answer to the questions of volumes are given as follows

a) v=128 \pi

b) v=\frac{128}{3} \pi

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Generally, the questions are  mathematically solved below

y=\sqrt{x}, y=4, x=0

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} v=\pi \int_{0}^{16}(\sqrt{x})^{2} d x \\

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b)  line y=4

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Using shell method

v = \int_{0}^{4} 2 \pi(4-y) \cdot y^{2} d y \\

v=2 \pi \int_{0}^{4}\left(4 y^{2}-y^{3}\right) d y

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c) y-axis

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v=\pi\left(\frac{y 5}{5}\right)_{0}^{4}  \\

v=\frac{1024}{5} \pi

d) line x=-1

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0 ≤ x ≤ 6

Using shell method

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V=\int_{0}^{16} 2 \pi(1+x) \sqrt{x} d x$

V=2 \pi\int_{0}^{16}(x^{1 / 2}+x^{3 / 2}\right) )d x\right. \\

V=2 \pi\left[\frac{x^{3 / 2}}{3 / 2}+\frac{x^{5 / 2}}{5 / 2}\right]_{0}^{16} \\

V=2 \pi\left[2 / 3 \cdot\left(4^{2}\right)^{3 / 2}+2 / 5\left(4^{2}\right)^{5 / 2}\right] \\

V=4 \pi / 3 \cdot 4^{3}+4 \pi / 5 \cdot 4^{5} \\

V=4 \pi\left(\frac{1}{3}+\frac{4^{2}}{5}\right)

V=\frac{256}{15}(5+48) \pi \\

V=\frac{256 \times 53}{15} \pi \\

V=\frac{13568}{15} \pi

Read more about volumes

brainly.com/question/1578538

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Which function has zeros at x=23 and x=−4?
VLD [36.1K]

Answer:

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Step-by-step explanation:

Weren't there possible answer choices to share?

if this function has zeros at 23 and -4, then the function has the following form:

g(x) = a(x - 23)(x + 4)

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