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3 years ago

5

What’s the correct answer

2 answers:

Jet001 [13]3 years ago

6 0

I think the answer is d

Vesnalui [34]3 years ago

3 0

The correct answer is B because if you count the numbers that are more than 35 and less than 56 is 8

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The height of a cone is twice the radius of its base.

amm1812

Answer:

The correct answer is option 1. $\frac{2}{3} \pi x^3$ cubic units.

Step-by-step explanation:

The formula for the volume, V of a right angled cone is given as:

$V = \dfrac{1}{3} \pi r^{2} h ...... (1)$

Where, $\pi = 3.14$

$r$ is the radius of the circular base of the cone.

$h$ is the height of the cone.

We are given that height is twice of the radius of its base.

Let the radius of base = $x$ units

Now, As per the question statement,

The height of cone= $2 \times x$ units

Putting the values of $r, h$ in equation (1) to find the volume:

$\Rightarrow \dfrac{1}{3} \times \pi \times x^{2} \times 2x\\\Rightarrow \dfrac{2}{3}\pi x^{3}$

Hence, the correct answer is option 1. $\dfrac{2}{3}\pi x^{3}$ cubic units.

3 0

3 years ago

Which expressions are equivalent to -3/16?

AysviL [449]

3/-16, - 3/16, -(3/16)

3 0

3 years ago

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How to write in equation in slope intercept form from graph

IceJOKER [234]

Answer:

mx+b

m=slope

b=y-intercept

Step-by-step explanation:

5 0

3 years ago

SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

2 years ago

What is 5/7-(-1/7) as a fraction?

Tanzania [10]

$\frac{5}{7} - \frac{1}{7}$

8 0

3 years ago

Read 2 more answers