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hjlf
3 years ago
6

The difference of sample means of two populations is 108.7, and the standard deviation of the difference in sample means is 32.

Which statement is true if we are testing the null hypothesis at the 68% confidence level?
A. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be rejected.

B. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be accepted.

C. The difference of the two means is not significant at the 68% confidence level, so the null hypothesis must be rejected.

D. The difference of the two means is not significant at the 68% confidence level, so the null hypothesis must be accepted.
Mathematics
1 answer:
charle [14.2K]3 years ago
5 0

Answer: A. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be rejected.

Step-by-step explanation:

I just got it right on PLATO, so I know it’s 100% correct.

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If ED = x + 4 and DB = 3x - 8, find ED, DB, and EB
Tom [10]

Answer:

Part 1) ED=10\ units

Part 2) DB=10\ units

Part 3) EB=20\ units

Step-by-step explanation:

we know that

EB=ED+DB

ED=DB -----> given problem

Substitute the given values and solve for x

x+4=3x-8

3x-x=4+8

2x=12

x=6

<em>Find the value of ED</em>

ED=x+4

substitute the value of x

ED=6+4=10\ units

<em>Find the value of DB</em>

Remember that

ED=DB

therefore

DB=10\ units

<em>Find the value of EB</em>

EB=ED+DB

EB=10+10=20\ units

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Step-by-step explanation:

an easier way to do this is simply by multiplying 47.40x115%, which is 54.51.

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