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Scrat [10]
3 years ago
8

Ppppppppppllllllllls I need helppppppp​

Mathematics
1 answer:
Phantasy [73]3 years ago
5 0

Answer:

ΔABC≅ΔDEC by AAS

Step-by-step explanation:

You can use the AAS method of congruency.

Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent

Hope this helped.

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millie needs the average height of the plants she is buying to be at least 73 inches. she has selected three plants that are 70,
Igoryamba
We are given with:
Average height of plants to be at least 73 inches

Three plants with heights of
70, 71, 72

The inequality that can be used to determine the possible heights of the fourth plant is:
(70 + 71 + 72 + x) / 4 ≥ 73
Solving for x
x ≥ 79
4 0
3 years ago
Find the x !<br> please hurry! Thank you!
wolverine [178]

Step-by-step explanation:

2x+98=180° (angles in straight line )

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2 years ago
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A triangle has angles measuring 43° and 62°. What is the measure of the triangle's third angle?
jarptica [38.1K]

Answer:

75 degrees

Step-by-step explanation:

I know the measure of the triangle's third angle is 75 degrees because all the angles of a triangle add up to 180 degrees. So, I did 180-62-43 and got 75. So, in order for this triangle to be true, the third triangle would have to be 75 degrees.

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3 years ago
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What is the length of the altitude of the equilateral triangle below?
Mazyrski [523]

ANSWER

The length of the altitude is 3\sqrt{3} units


<u>EXPLANATION</u>

The altitude of a triangle is the vertical height of the triangle.


From the diagram the altitude is a


Method 1: We can use Pythagoras theorem to find a


6^2=a^2+3^2


6^2-3^2=a^2


36-9=a^2


27=a^2


We take the square root of both sides,

\sqrt{27}=a


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\sqrt{9} \times \sqrt{3}=a


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Method 2 Using Trigonometry

sin(60\degree)=\frac{a}{6}

6sin(60\degree)=a


a=6\times \frac{\sqrt{3}} {2}


a=3\sqrt{3}






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3 years ago
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