Question

PLEASE HELP I'LL GIVE BRAINLIEST!!! The first barn contained 3 times more hay than the second one. After 20 tons of hay were removed from the first barn and 20 tons were added to the second barn, the amount of hay in the second barn was 5/7 of the amount remaining in the first barn. How many tons of hay was there in each barn?

Answer 1

Answer:

First Barn contained = 90 tons

Second barn contained = 30 tons

Step-by-step explanation:

Let us suppose that second barn contains x tons of Hay

Now according to given condition

First Barn Contain = 3 *x = 3x

According to other condition

20 tons removed from first barn i.e. 3x - 20 and 20 tons were added to second barn i.e. x + 20

the amount of hay in second barn which is x + 20 is equal to 5 / 7 of the hay remaining in first barn which is 3x-20

So in mathematical form it could be written as

x + 20 = $\frac{5}{7}*(3x-20)$

To find hay in each barn

We have the equation

x + 20 = $\frac{5}{7}*(3x-20)$

Multiplying both sides of equation by 7

7(x+20)=$\frac{5*7}{7}*(3x-20)$

7(x+20)=5(3x-20)

7x + 140 = 15 x - 100

adding 100 on both sides gives

7x + 140 + 100 = 15x - 100 + 100

7x + 240 = 15 x

Subtracting 7x from both sides

7x + 240 - 7x = 15 x - 7x

240 = 8x

or

8x = 240

Dividing both sides by 8

8x / 8 = 240 / 8

x = 30 tons

so second barn contained = 30 tons of hay

now

First barn contained = 3 * x

as x = 30

so putting the value

First barn contained = 3 * 30

First Barn contained = 90 tons