Answer:x=26
Step-by-step explanation:
Answer:
nothing
Step-by-step explanation:
there is no function graphs
Answer:
52
Step-by-step explanation:
Given:
AB = 10, AD =24
Required:
Value of AC + BD
SOLUTION:
AC = BD (both are diagonals of the rectangle)
Use pythagorean theorem to find AC.
Thus:
AB² + AD² = BD²
Plug in the values
10² + 24² = BD²
676 = BD²
√676 = BD
26 = BD
BD = AC = 26
Therefore,
AC + BD = 26 + 26 = 52
Answer:
p= 6q+7
-7. -7
p-7 =6q
/6. /6
p-7/6
Step-by-step explanation:
if you want to make a specific term the subject, you need to isolate it on one side of the equation. You do this by 'getting rid' of anything on the term's side of the equation, starting with whatever's furthest from the term. (think BEMDAS but backwards)
p = 6q + 7
(take 7 from both sides to get rid of +7 on q's side)
p - 7 = 6q + 7 - 7
p - 7 = 6q(divide both sides by 6 to get rid of 6 on q's side)
=
q=
49. From 3 coin tosses, there are 8 possible outcomes:
... TTT, TTH, THT, THH, HTT, HTH, HHT, HHH
All but the first have at least one head, so 7/8 of the possibilities have at least one head. That's 87.5% (not among your choices).
Likewise, all but the last listed outcome have at least one tail. The problem is symmetrical that way when the coin is fair. 87.5% of outcomes have at least one tail.
___
Perhaps you can tell I read your question as having two parts. If your question is the probability of getting at least one head AND at least one tail, you can see that condition includes 6 of the 8 outcomes, or 75%, matching selection d.
50. See for yourself: the calculator says 66.82%. Your best choice is selection d.