Answer: a) 
b) 1
c) 2
Step-by-step explanation:
(a) sin 17π/6
It is known that the value of sin x repeat after an interval of 
∴ 
[Since the value of sin x is positive in 2nd quadrant]
(b) tan 13π/4
It is known that the value of sin x repeat after an interval of 
∴ 
(c) sec 11π/3
2cos(x) - 4sin(x) = 3
use identity [cos(x)]^2 +[ sin(x)]^2 = 1 => cos(x) = √[1 - (sin(x))^2]
2√[1 - (sin(x))^2] - 4 sin(x) = 3
2√[1 - (sin(x))^2] = 3 + 4 sin(x)
square both sides
4[1 - (sin(x))^2] = 9 + 24 sin(x) + 16 (sin(x))^2
expand, reagrup and add like terms
4 - 4[sin(x)]^2 = 9 + 24sin(x) + 16sin^2(x)
20[sin(x)]^2 + 24sin(x) +5 = 0
use quadratic formula and you get sin(x) = -0.93166 and sin(x) = -0.26834
Now use the inverse functions to find x:
arcsin(-0.93166) = 76.33 degrees
arcsin(-0.26834) = 17.30 degrees
False test with 10 questions
Answer: B (0.17, 2.33)
Step-by-step explanation:
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