If a triangle has sides of 7 cm and it is an equilateral you can draw a line right down the middle to form two congruent triangles.
These smaller triangles have a hypotenuse of 7cm and a base of 3.5 cm (7/2)
To work out the height, use Pythagoras’ theorem.
a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the other two sides
7^2 - 3.5^2 = 36.75
Square root answer
= 6.06 cm
That’s the height of the triangle
Area of a triangle is base x height divided by 2
So 7 x 6.06 = 42.43…
/2
= 21.2 cm^2 to one d.p
Hope this helped!
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Given:
Side length of base = 8
Slant height = 6
To find:
The surface area of the square pyramid.
Solution:
Surface area:
where A is the area of base
p is the perimeter of base
s is the slant height
Area of base (A) = 8 × 8
= 64
Perimeter of base(P) = 4 × 8
= 32
Substitute these in the formula:
The surface area of the square pyramid is 160 unit².
Answer:
8y^2 (y+2)
Step-by-step explanation:
8y^3 + 16y^2
both terms contain an 8 and a y^2 so we can factor them out
8y^2 (y+2)
