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maks197457 [2]
2 years ago
9

Can someone pleaseeee help and if you’re correct i’ll give brainliest

Mathematics
2 answers:
deff fn [24]2 years ago
8 0

Answer:

The answer should be 13.

Strike441 [17]2 years ago
8 0
13 centimeters ? because 1cm + 8cm + 4cm = 13cm
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use counters model to solve this problem.eva has 2 apples in her basket.She eats 1 apple and gives 1 to her friend.How many appl
barxatty [35]

A: She Has 0

E: she had 2 she ate one and gave one away

2 - 1 =1

1 - 1 = 0

3 0
2 years ago
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Max invests some money in a savings bond.
Mars2501 [29]

Answer:

£5650

Step-by-step explanation:

The money max invested in the saving bond = x

After one year the intrest will be 2% of x

Amount = £5763

Amount = Principcal + Interest

= £5763 = x + 2% multiplied x

£5763 = x + 2x/100

= 50x/50 + x/50 = 5763

= 51x/50 = £5763

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x = 5650

So the money max invested = £5650

7 0
2 years ago
Maddi has a bin shaped like a right prism. She knows that the area of the base of the bin is 14 in² and the volume of the bin is
Oksana_A [137]

Answer:

The answer is 28 in

Step-by-step explanation:

I divided 392/14=28

hopefully it helps.

please mark brainliest.

8 0
1 year ago
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PLEASEEEE HELP!!!<br> Which equation should you solve to find x?
ziro4ka [17]

Answer:

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3 0
2 years ago
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Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or
soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

\lim_{x \to 3} f(x)

f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L

and the limit does not exist if

\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)

Evaluate the one-sided limits.

The left-hand limit

\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0

The right-hand limit

\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6

Because the limits are not the same the limit does not exist.

8 0
3 years ago
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