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Alex73 [517]
2 years ago
7

In rats, the allele for long whiskers is dominant to the allele for short whiskers. At another gene locus, a dominant allele pro

duces whiskers and the recessive allele produces a rat with no whiskers. The alleles at these 2 gene loci assort independently. If a rat that is homozygous for both recessive alleles is crossed with a rat that is heterozygous at both gene loci, what percentage of the offspring are expected to have short whiskers? ( Enter the number only without the percent sign. For example, enter 100% as 100 and enter 12.5% as 12.5 )

Biology
1 answer:
PilotLPTM [1.2K]2 years ago
3 0

Answer:

25%

Explanation:

We have 2 independent genes with 2 alleles each: L/l and W/w

  • W_: whiskers
  • ww: no whiskers
  • L_: long whiskers
  • ll: short wiskers

Individuals with short whiskers will have the genotype <em>WWll </em>or <em>Wwll</em>.

<u>A cross between a rat heterozygous for both genes and a homozygous recessive rat is done:</u>

<h3>WwLl x wwll</h3>

-The homozygous rat will produce only <em>wl </em>gametes.

-The heterozygous rat will produce the following gametes: <em>WL</em>, <em>Wl</em>, <em>wL</em>, <em>wl</em>.

If you do a Punnett Square, you'll get that 25% of the offspring will be WwLl and will have short whiskers.

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