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Tamiku [17]
3 years ago
11

the dimensions shown are an approximation using these dimensions which is the approximate area of abc

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0
What are the dimensions shown?
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What is the equation of log x 729=3?
pishuonlain [190]

Answer:

Step-by-step explanation:

Move 729  to the left side of the equation by subtracting it from both sides.  x  3 − 729  = 0  Factor the left side of the equation.  Rewrite  729  as 9

3

.  x

3

−

9

3

=

0

. Since both terms are perfect cubes, factor using the difference of cubes formula,  a

3

−

b

3

=

(

a

−

b

)

(

a

2+ab+b2). Where a

=x and  b=9. (x−9)(x2+x⋅9+92)=0

. Simplify.  Move 9  to the left of x

.  (x−9)(x2+9x+92)=0.  Raise  9  to the power of 2

.  (x

−9

)(

x

2

+

9

x

+81

)=0

. Set x

−9  equal to  0 and solve for x.  Set the factor equal to  0. x−

9=

0. Add 9  to both sides of the equation.  x=9

. Set x2+

9

x

+

81 equal to  0  and solve for  x

.  Set the factor equal to 0

.  x2+9x+81=0.  Use the quadratic formula to find the solutions.  −b±√b2−4(ac) 2a. Substitute the values  a=1, b=9, and c=81  into the quadratic formula and solve for  x.  −9±√92−4⋅ (1⋅81

) 2⋅

1  Simplify.  Simplify the numerator. Raise 9  to the power of 2. x=−9±√81−4⋅(1⋅81) 2⋅1. Multiply  

81

by  

1

.

x

=

−

9

±

√

81

−

4

⋅

81

2

⋅

1

Multiply  

−

4

by  

81

.

x

=

−

9

±

√

81

−

324

2

⋅

1

Subtract  

324

from  

81

.

x

=

−

9

±

√

−

243

2

⋅

1

Rewrite  

−

243

as  

−

1

(

243

)

.

x

=

−

9

±

√

−

1

⋅

243

2

⋅

1

Rewrite  

√

−

1

(

243

)

as  

√

−

1

⋅

√

243

.

x

=

−

9

±

√

−

1

⋅

√

243

2

⋅

1

Rewrite  

√

−

1

as  

i

.

x

=

−

9

±

i

⋅

√

243

2

⋅

1

Rewrite  

243

as  

9

2

⋅

3

.

Tap for fewer steps...

Factor  

81

out of  

243

.

x

=

−

9

±

i

⋅

√

81

(

3

)

2

⋅

1

Rewrite  

81

as  

9

2

.

x

=

−

9

±

i

⋅

√

9

2

⋅

3

2

⋅

1

Pull terms out from under the radical.

x

=

−

9

±

i

⋅

(

9

√

3

)

2

⋅

1

Move  

9

to the left of  

i

.

x

=

−

9

±

9

i

√

3

2

⋅

1

Multiply  

2

by  

1

.

x

=

−

9

±

9

i

√

3

2

Factor  

−

1

out of  

−

9

±

9

i

√

3

.

x

=

−

1

9

±

9

i

√

3

2

Multiply  

−

1

by  

−

1

.

x

=

1

−

9

±

9

i

√

3

2

Multiply  

−

9

±

9

i

√

3

by  

1

.

x

=

−

9

±

9

i

√

3

2

The final answer is the combination of both solutions.

x

=

−

9

−

9

i

√

3

2

,

−

9

+

9

i

√

3

2

The solution is the result of  

x

−

9

=

0

and  

x

2

+

9

x

+

81

=

0

.

x

=

9

,

−

9

−

9

i

√

3

2

,

−

9

+

i

√

3

2

7 0
4 years ago
A 9-kg bag of mangoes for $12
sertanlavr [38]
Mangos are pretty good
5 0
3 years ago
Please help me!
marusya05 [52]

Answer:


Step-by-step explanation:

Nice summary problem.

<AEC

  • AEC = 360 - 243.5 = 116.5    
  • The number of degrees in 1 rotation of a circle = 360o. You have accounted for 243.5 degrees. What is left over is the answer.

<EAD and <ECD

Both of these are tangents to a circle. Tangents meet radii at 90 degree angles.

<EAD = <ECD = 90 degrees

<ABC

<ABC is 1/2 the central angle. The Central angle is <AEC

  • < AEC = 116.5
  • <ABC = 1/2 * 116.5
  • <ABC = 58.25

<ADC

There are 2 ways of doing this. You should know both of them.

<em><u>One</u></em>

All quadrilaterals = 360 degrees. You know three of the angles. You should be able to find ADC

  • <ADC + 90 + 90 + 116.5 = 360     Add the four angles together.
  • <ADC + 296.5 = 360                   Combine terms on the left
  • <ADC = 360 - 296.5                    Subtract 238.25 from both sides
  • <ADC = 63.5                                 Answer

<em><u>Method Two</u></em>

<ADC = 1/2 (major Arc - Minor Arc)  This formula is fundamental to circle / tangent properties. The Major arc is the larger of the two parts of the circumference of a circle. The Minor arc is the smaller.

  • <ADC = 1/2(243.5 - 116.5)
  • <ADC = 1/2(127)
  • <ADC = 63.5
8 0
3 years ago
51. (08.02 MC) Box A has a volume of 48 cubic meters. Box B is similar to box A. To create Box B, Box A's dimensions were double
Vanyuwa [196]

Answer:

384 m³

Step-by-step explanation:

Let the dimension of box a be l,b, and h.

ATQ,

lbh = 48 .....(1)

If we double the dimension of box A, we get box B whose new dimensions will be 2l,2b and 2h.

Let V be the volume of box B.

V = (2l)(2b)(2h)

V = 8(lbh)

= 8(48) [from equation (1)]

= 384 m³

Hence, the volume of the box B is 384 m³.

7 0
3 years ago
FIRST TO ANSWER GET BRAINLEST.
Lostsunrise [7]

Answer:

I believe the answer is B sorry if I'm wrong

3 0
3 years ago
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