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EleoNora [17]
3 years ago
15

James is a welder who earns $18 per hour. He works 8 hours per day, Monday through Friday. How much does James earn in one week?

Mathematics
2 answers:
BigorU [14]3 years ago
5 0

Answer:

720 Dollars a Week

Step-by-step explanation:

18x8x5

since he makes 18 dollars an hour you multi that by 8 because 8 hours

then you have to multiply that by 5 because he works 5 days a week mon-fri

Alex3 years ago
4 0
720 8 times 18 times 4
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Hello can anyone help me ? here the question
lesantik [10]

Answer:

A. 1/5k - 2/3j and -2/3j +1/5k

Step-by-step explanation:

A. 1/5k - 2/3j and -2/3j +1/5k

B. 1/5k - 2/3j and -1/5k +2/3j

There is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

Not equivalent

C. 1/5k - 2/3j and 1/5j - 2/3k

There is a change in the variables

1/5k changed to 1/5j

-2/3j changed to -2/3k

D. 1/5k - 2/3j and 2/3j - 1/5k

The is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

The only equivalent expression is

A. 1/5k - 2/3j and -2/3j +1/5k

3 0
3 years ago
A system of equations is shown below:
gtnhenbr [62]
Y = 8x - 2
y = 9x - 7

  8x - 2 = 9x - 7
- 8x       - 8x
        -2 = x - 7
      + 7      + 7
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y = 8x -2
y = 8(5) - 2
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8 0
4 years ago
The claim that 40% of those persons who retired from an industrial job before the age of 60 would return to work if a suitable j
Bad White [126]

Answer:

The p-value of the test is of 0.1922 > 0.02, which means that there is not significant evidence to reject the null hypothesis, that is, there is not significant evidence to conclude that the proportion is of less than 40%.

Step-by-step explanation:

Test if the proportion is less than 40%:

At the null hypothesis, we test if the proportion is of at least 0.4, that is:

H_0: p \geq 0.4

At the alternative hypothesis, we test if the proportion is of less than 0.4, that is:

H_1: p < 0.4

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that \mu = 0.4, \sigma = \sqrt{0.4*0.6}

74 out of the 200 workers sampled said they would return to work

This means that n = 200, X = \frac{74}{200} = 0.37

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.37 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}

z = -0.87

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.37, which is the p-value of z = -0.87.

Looking at the z-table, z = -0.87 has a p-value of 0.1922.

The p-value of the test is of 0.1922 > 0.02, which means that there is not significant evidence to reject the null hypothesis, that is, there is not significant evidence to conclude that the proportion is of less than 40%.

7 0
3 years ago
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