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Lina20 [59]
3 years ago
12

Please help and show work!!

Mathematics
1 answer:
stepan [7]3 years ago
7 0
One pound is equal to 16 ounces. so to do this you would need to multiply 5 by 16 to get 80 ounces total. Then you would subtract the 12 from the 80 since she gave it away and it isn't included in the bags that she is giving out.this leaves you with 68 ounces. Finally, you would divide 68 by 4 to get 17. She made a total of 17 bags of trail mix. 
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Using the quadratic formula, what are the solutions to x2 – 3x = -2?
Kryger [21]

Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
The sprit club is making school jackets to sell. The cost c (in dollars) for silkscreening supplies and jackets is c=20x+270, wh
lys-0071 [83]

Answer:

The club must sell 18 jackets to break even

Step-by-step explanation:

Given:

C = 20x + 270

Where,

x = number of jackets

Equation for revenue R in terms of the number of jackets

Revenue = price × quantity

Price of the jacket = $35

Quantity of the jacket = x

Revenue = price × quantity

= 35 * x

R = 35x

Break even point is the point at which cost is equal to revenue, that is, no gain; no loss.

Cost = revenue

20x + 270 = 35x

270 = 35x - 20x

270 = 15x

x = 270 / 15

= 18

x = 18 jackets

The club must sell 18 jackets to break even

3 0
3 years ago
Read 2 more answers
I need help in this question
tiny-mole [99]

Answer:

C. 12/15

Step-by-step explanation:

2/3, 6/9, and 18/27 all simplify to 2/3. 12/15 does not.

8 0
2 years ago
What is the distance between -4 and 7 on a number line?
tiny-mole [99]

Answer:

11

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLS HELP ME!!! which matrix represents the system of equations below {8x-9y+13z=11
Finger [1]

Answer:

The answer is below

Step-by-step explanation:

The system of equations:

8x-9y+13z=11

-8x-5y+5z=15

3x+4y-8z=-10

The equations can be represented in matrix form as:

AX = B

X = A⁻¹B

Therefore:

\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] ^{-1}\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\

\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}\frac{1}{19} &-\frac{1}{19}&\frac{1}{19}\\-\frac{49}{380}&-\frac{103}{380}&-\frac{36}{95} \\-\frac{17}{380}&-\frac{69}{380}&-\frac{28}{95} \end{array}\right] \left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}-0.74\\-1.69\\0.13\end{array}\right] \\

4 0
3 years ago
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