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Citrus2011 [14]
3 years ago
12

Part 3: Use the information provided to write the standard form equation of each circle

Mathematics
2 answers:
ololo11 [35]3 years ago
8 0

Answer:

7. (x + 5)² + (y + 14)² = 9

8. (x - 1)² + (y - 10)² = 49

9. (x - 7)² + (y - 15)² = 25

Step-by-step explanation:

7. (x + 8)^2 + (y + 14)^2 = 9

Centre: (-8,-14)

Translated 3 right, 5 down

Centre: (-5,-19)

(x - (-5))² + (y - (-14))² = 9

(x + 5)² + (y + 14)² = 9

8. (x + 2)^2 - (y - 8)^2 = 49

Centre: (-2,8)

Translated 3 right, 2 up

Centre: (1,10)

(x - 1)² + (y - 10)² = 49

9. (x - 4)^2 + (y - 11)^2 = 25

Centre: (4,11)

Translated 3 right, 4 up

Centre: (7,15)

(x - 7)² + (y - 15)² = 25

Ber [7]3 years ago
4 0

Answer:

9. \displaystyle (x - 7)^2 + (y - 15)^2 = 25

8. \displaystyle (x - 1)^2 - (y - 10)^2 = 49

7. \displaystyle (x + 5)^2 + (y + 19)^2 = 9

Step-by-step explanation:

\displaystyle [x - h]^2 - [y - k]^2 = r^2 → Hyperbola\:Equation \\ [x - h]^2 + [y - k]^2 = r^2 → Circle\:Equation \\ [h, k] → Centre

According to the equations in the exercises, in the parentheses, ALL NEGATIVE SIGNS give the OPPOSITE terms of what they REALLY are, so be EXTREMELY CAREFUL with your translations:

9. [4, 11]

+ 3 + 4

_____

[7, 15] → (x - 7)² and (y - 15)²

8. [−2, 8]

+ 3 + 2

_____

[1, 10] → (x - 1)² and (y - 10)²

7. [−8, −14]

+ 3 - 5

______

[−5, −19] → (x + 5)² and (y + 19)²

** NOTISE THAT THE RADII <em>NEVER</em><em> </em>ALTER.

I am joyous to assist you anytime.

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spayn [35]

Answer:

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Step-by-step explanation:

y2+5y-24

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3 years ago
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Georgia [21]

Answer:

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2-Do 15 times 2 and then 15 times 10. Add the sums together

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Step-by-step explanation:

7 0
4 years ago
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irakobra [83]
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8 0
3 years ago
Which equation has exactly two real and two non real solutions?
tatiyna

Answer:

The first option x^4-21x^2-100=0.

Step-by-step explanation:

To have exactly 2 real and two non real solutions, the degree of the polynomial must be a degree 4. Degree is the highest exponent value in the polynomial and is also the number of solutions to the polynomial. This polynomial ha 2 real+2 non real= 4 solutions and must be x^4. This eliminates the bottom two solutions.

In order to have two real and two non real solutions, the polynomial must factor. If it factors all the way like

x^4-100x^2=0\\x^2(x^2-100)=0\\x^2(x-10)(x+10)=0\\\\x^2=0\\x-10=0\\x+10=0

This means x=0, 10, -10 are real solutions to the polynomial. It has no non real solutions. This eliminates this answer choice.

Only answer choice 1 meets the requirement.

5 0
4 years ago
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Step-by-step explanation:

1/340=0.00294118

5 0
4 years ago
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