You can convert (1/625) to an exponent, and it would be ideal to have 5 as the base of it because you want your log base to cancel it out. what i usually do in this case is just test out 5^1, 5^2, etc until i find one that matches the number i need. in this case because the number you're trying to work with is a small fraction, you'll want to use NEGATIVE exponents so it'll create a fraction instead of a large whole number:
5^-1 = 1/5
. . . keep trying those. . .
5^-4 = 1/625
so, because they're equal to one another, it'll be waaay easier after you substitute 5^-4 in place of 1/625
x = log₅ 5⁻⁴
log base 5 of 5 simplifies to 1. subbing in the 5^-4 gets rid of the log for you altogether, and your -4 exponent drops down:
x = -4 is your answer
if the exponent dropping down doesn't make sense to you, you can think of it in another way:
x = log₅ 5⁻⁴
expand the expression so that the exponent moves in front of the log function:
x = (-4) log₅ 5
then, still, log base 5 of 5 simplifies to 1, so you're left with:
x = (-4)1 or x = -4
If you mean 46 * 3 = 138
If you mean 46 + 3 = 49
If you mean 46 - 3 = 43
If you mean<span> 46 ÷ 3 = 15.3
Hope it helped
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Answer:
The third one counting from the top.
Step-by-step explanation:
We have the inequality:
(-1/3)*(2x + 1) < 3
The first thing we need to do is isolate x on one side of the inequality.
First we can by -3 in both sides of the inequality, and remember, because we are multiplying by a negative number, the inequality sign changes its direction:
(-3)*(-1/3)*(2x + 1) > 3*(-3)
(2x + 1) > -9
Now we can subtract 1 in both sides:
2*x + 1 - 1 > -9 - 1
2*x > -10
Now we can divide by 2 in both sides:
2*x/2 > -10/2
x > -5
Then we should see a number line such that all the points at the right of -5 are colored.
The correct option is the third one, counting from the top.
Answer:
C. volume
Step-by-step explanation:
when youre starting your measurements you want to start the volume first.
Answer:
I believe it would be 21 units . dont let extra line's confuse you just pay attention to the letters its asking for
