Answer:
7/8−6/11=29/88
Step-by-step explanation:
i used a calculator.
hope this helps :))
Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
Answer:
12
Step-by-step explanation:
AC = BD (as the diagonal of the rectangle)
4x-60=30-x
4x+x = 30+60
5x = 90
x = 90/5
x = 18
=> BD = 30-18 = 12
I got 2.2
Step-by-step explanation:
I probably did the math wrong but i did my best and i hope this helped even a little!
Answer:
Step-by-step explanation:
You can readily see from the diagram, above, that the side length of the middle cube will be between 3 and 4. You want to determine to the nearest hundredth what value between 3 and 4 represents the side length of the cube whose volume is 45 units^3.
Please note: the middle cube has been mislabeled. Instead of volume = 30 units^3, the volume should be 45 units^3.
Here's the procedure:
Guess an appropriate s value. Let's try s = side length = 3.5
Cube this: (3.5 units)^3 = 42.875. Too small. Choose a larger possible side length, such as 3.7: 3.7^3 = 50.653. Too large.
Try s = 3.6: 3.6^3 = 46.66. Too large.
Choose a smaller s, one between 3.5 and 3.6: 3.55^3 = 44.73. This is the best estimate yet for s. Continue this work just a little further. Try s = 3.57. Cube it. How close is the result to 45 cubic units?
