1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kvv77 [185]
2 years ago
11

The manufacturer of a laser printer reports the mean number of pages a cartridge will print before it needs replacing is 12,425.

the distribution of pages printed per cartridge closely follows the normal probability distribution and the standard deviation is 595 pages. the manufacturer wants to provide guidelines to potential customers as to how long they can expect a cartridge to last. how many pages should the manufacturer advertise for each cartridge if it wants to be correct 99 percent of the time?

Mathematics
1 answer:
snow_lady [41]2 years ago
8 0

A suitable probability app shows the 1st percentile to be at about 11040 pages.

_____

The app shown has an error in the first decimal digit. The number is closer to 11040.82301. We expect the manufacturer would round to the nearest 10 or 50 or 100 in advertising.

You might be interested in
(EXTRA POINTS) Which of the following relations is a function?<br><br><br><br> file in question
Taya2010 [7]
I think it is a I am not sure though
6 0
3 years ago
What is the product of this binomial (2x + 4y)(x + 2y)
Anon25 [30]
2x^2+8xy+8y^2
2(x^2+4xy+4y^2)
4 0
2 years ago
A past survey of students taking a standardized test revealed that ​% of the students were planning on studying engineering in c
Angelina_Jolie [31]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

The  95% confidence interval is  -0.00870

Step-by-step explanation:

From the question we are told that

     The first sample  size  is  n_1  =  1068000

     The first proportion  \r p_1 = 0.084

     The second  sample size is  n_2  =  1476000

     The  second  proportion is  \r p_2 =  0.092

Given that the confidence level is  95%  then the level of significance is mathematically represented as

      \alpha =  (100 - 95)\%

     \alpha =  0.05

From the normal distribution table  we obtain the critical value of  \frac{ \alpha }{2}  the value is  

      Z_{\frac{\alpha }{2} } =z_c=  1.96

Now using the formula from the question to construct the 95% confidence interval we have  

  (\r p_1 - \r p_2  )- z_c \sqrt{ \frac{\r p_1 \r q_1 }{n_1} + \frac{\r p_2 \r q_2 }{n_2} }

Here \r q_1 =  1 - \r p_1

  =>   \r q_1 =  1 - 0.084

 =>    \r q =  0.916

and  

   \r q_2 =  1 - \r p_2

 =>   \r q_2 =  1 - 0.092

=>   \r q_2 = 0.908

So  

 (0.084 - 0.092 )- (1.96)*  \sqrt{ \frac{0.092* 0.916 }{1068000} + \frac{0.084* 0.908 }{1476000} }

  -0.00870

 

3 0
3 years ago
What is the surface area of a box that is 6 by 4 inches
san4es73 [151]

Answer:

The surface area of a box that is 6 by 4 inches is 24in²

6 0
2 years ago
Read 2 more answers
Need help wit this right now
Sliva [168]

Answer:

g (x) = f(x-5)

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • Solve x:12 : x = 8:6<br> plase help this means a lot to me
    12·1 answer
  • if a plane leave the ski resort every hour. the first plane leaves at 10 and the second plane leaves at 4 how man planes leave e
    11·1 answer
  • Can somebody help???
    9·2 answers
  • What are the factors of x2 – 144? And
    12·2 answers
  • Whoever checks my work and tell what I did wrong and the right answer will
    9·1 answer
  • What is 24/(6 x 2) in numerical expression using words
    9·1 answer
  • Hey guys can you please help me out with my math homework
    11·1 answer
  • 43. Find the image of the point (1,2) when reflected<br>by the line x=-1​
    12·1 answer
  • Bütünler iki açıdan büyük olanın ölçüsü küçük olanın ölçüsünün 4 katından 10°eksiktir. Buna göre büyük açı kaç derecedir?​
    7·1 answer
  • PQRS is a parralelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j. find the position vector of P
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!