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LenKa [72]
3 years ago
12

7 in.

Mathematics
1 answer:
Inessa [10]3 years ago
8 0

Answer:

7 x 7 x 8 = 392

15 x 7 x 7(14 - 7) = 735

735 + 392 = 1,127 in^3 is your answer.

Let's split the figure:

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Help plz I'm desperate ​
lutik1710 [3]

<u>Anna:</u>

1st month = 18 + \frac{3}{4} = 18\frac{3}{4} inches

2nd month = 18\frac{3}{4} + \frac{3}{4} = 19\frac{1}{2}

3rd month = 19\frac{1}{2} + \frac{3}{4} = 20\frac{1}{4}

4th month = 20\frac{1}{4} + \frac{3}{4} = 21

5th month = 21 + \frac{3}{4} = 21\frac{3}{4}

<u>Grace:</u>

Because Anna is \frac{9}{4} inches shorter than Grace, we can start the count from the third month:

1st month = 20\frac{1}{4}

2nd month = 21

3rd month = 21\frac{3}{4}

4th month = 21\frac{3}{4} + \frac{3}{4} = 22\frac{1}{2}

5th month = 22\frac{1}{2} + \frac{3}{4} = 23

7 0
3 years ago
Express the number in scientific notation. 780,000,000
Aloiza [94]
Scientific notation implies that all the zeros are taken away and replaced with a 10 raised to whatever appropriate power would be necessary to make the number in scientific notation equal to the original number.

In the number 780,000,000, we can see that there are 7 zeros, but the number before the zeros has two digits, so we need to tuck the decimal point in there, because the number has to be between 1 and 10 for math reasons.

7.8 ... but what do we raise it to? We know it has to be 10, but to what power? Well, we just count how many places to the left the decimal point has traveled. From the original number, the decimal point shifted 8 places to the left, so that is the number that we will raise the 10 to.

The final number looks like this:

7.8 * 10^8

780,000,000 in scientific notation is <span>7.8 * 10^8
Hope that helped =)</span>
4 0
3 years ago
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Neporo4naja [7]
The first interception for this function would be at (1,0) the next would be (4,0)
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What is the solution, if any, to the inequality |3x| ≥0?
Yanka [14]

Answer:

the answer is either c or b

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3 years ago
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Help me pleaseee.....
Lana71 [14]

Answer:

titutex=cos\alp,\alp∈[0:;π]

\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+

1−x

2

∣=

2

(2x

2

−1)\Leftright∣cos\alp+sin\alp∣=

2

(2cos

2

\alp−1)

\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N

2

cos(\alp−

4

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)∣=N

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cos(2\alp)\Right\alp∈[0;

4

π

]∪[

4

3π

;π]

1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;

4

π

]

\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−

4

π

)=cos(2\alp)…

2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[

4

3π

;π]

\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−

4

π

)=cos(2\alp)…

1

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6 0
3 years ago
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