2002=25,160
2001=22,644
2000=19,926.72 (need to round to 19,926)
2001:
25,160/10=2516
25,160-2516
2000:
22,644/10=2,264.4 (10%)
2,264.4/5=452.88 (2%)
2,264.4+452.88=2717.28 (12%)
22,644-2717.28=19.926.72
So when X is 0, the area of the pool is 1200. That makes A and C impossible... then you can plug in numbers...say the boardwalk is 1 ft wide, add 2 to each dimension and plug in 1 for X. (You're adding 2 because there is a tile on either side of each dimension, including corners).
32x42=1344=4+140+1200
Therefore the answer is B.
Let the weight of the first truck be represented by w.
total weight = w + (2 + w) + (2 + 2 + w) + (2 + 2 + 2 + w)
32 = 4w + 12
20 = 4w
w = 5
Therefore, the first truck weighs 5 tons, the second weighs 7 tons, the third weighs 9 tons and the fourth weighs 11 tons.
Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
