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Jet001 [13]
3 years ago
7

The triangle above is a right triangle with side lengths a = 7 in, b = 24 in, and c= 25 in.

Mathematics
1 answer:
Zigmanuir [339]3 years ago
7 0

Answer:

the sum of the squares of the two smaller sides is equal to the square of the third and longer side.

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Give another name for RS.
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Answer:

Step-by-step explanation:

7 0
2 years ago
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Candice bought 4 notebooks that each cost the same amount. She paid with a $20 bill and received $10.32 in change. Write an equa
ohaa [14]

Answer:

(20-10.32)÷4=x

Step-by-step explanation:

6 0
2 years ago
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A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
What is the answer for #5
Andreyy89
A a and c.............
5 0
3 years ago
Verify that whether -2 and 3 are zeroes of the polynomial x^2-x=6<br>PLEASE HELP​
Anna35 [415]

Answer:

Both give remainder 0 for the polynomial

Step-by-step explanation:

p(-2) = (-2)² - (-2) - 6

= 6 - 6 = 0

p(3) = (3)² - 3 - 6

= 9 - 9 = 0

4 0
2 years ago
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