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ddd [48]
3 years ago
10

3. What is the value of "X" in this equation: x + 4 = 15" X19

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0

Answer:

x = 11

Step-by-step explanation:

x + 4 = 15

Subtract 4 from each side

x + 4-4 = 15-4

x  = 11

creativ13 [48]3 years ago
3 0

Answer:

x=2 i hope this helped f8tfuccr7yxr

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Find x. (Round final answer to the nearest tenth. Show all work.)
nataly862011 [7]

Answer:

Step-by-step explanation:

x is 12

3 0
3 years ago
A linear function contains the following points: 0,-3 and 6,15.
9966 [12]

The slope of the linear function is 3 and the y-intercept is -3 if the linear function contains the following points: (0,-3) and (6,15)

<h3>What is the slope?</h3>

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

\rm m =\dfrac{y_2-y_1}{x_2-x_1}

We have:

A linear function contains the following points: (0,-3) and (6,15)

The slope:

\rm m =\dfrac{15-(-3)}{6-0}

m = 18/6

m = 3

The equation of a line:

y = mx + c

Plug x = 0, y = -3

-3 = c

Thus, the slope of the linear function is 3 and the y-intercept is -3 if the linear function contains the following points: (0,-3) and (6,15)

Learn more about the slope here:

brainly.com/question/3605446

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4 0
2 years ago
Solve x(−2)3=−2(5). The solution is x=
Solnce55 [7]
Exact form : 5/3
decimal form : 1.6 repeating
mixed number form : 1 2/3
6 0
3 years ago
Lydia invested $8,300 in an account paying an interest rate of 2.2% compounded
Dennis_Churaev [7]

Answer:

1245

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve for x. 3(3x - 1) + 2(3 - x) = 0
olga nikolaevna [1]
The equation given in the question is
3(3x - 1) + 2(3 - x) = 0
9x - 3 + 6 - 3x = 0
6x + 3 = 0
6x = - 3
x = - (3/6)
   = - (1/2)
So the value of x as has been determined above is -1/2. I hope the procedure is clear enough for you to understand.<span>You can always use this method for solving problems that are similar in type without requiring any help from outside. </span>



8 0
3 years ago
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