You can replace the h and w with 6 and 3 in the expression. Then the expression is 12*6+30*3=162 dollars. So the amount paid to this employee is 162 dollars.
Let the third side = x.
The sum of any two sides must be greater than the third side
14 + 9 > x
23 > x
14 + x > 9
x > -5
9 + x > 14
x > 5
So 5 < x < 23
Answer:
52 dimes and 28 nickels
Step-by-step explanation:
n = number of nickels
d = number of dimes
n+d = 80 the number of coins he got
Multiply the number of nickels times .05 plus the number of dimes times .10 to equal the amount of money he got
.05n + .10d = 6.60
Divide this equation by .05
.05n/.05 + .10/.05 = 6.60/.05
n + 2d = 132
n+d = 80
Multiply by -1
-n-d=-80
Add this to n+2d = 132
n+2d=132
-n-d=-80
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d = 52
Now we need to solve for n
n+d = 80
n+52 = 80
Subtract 52 from each side
n+52-52= 80-52
n = 28
Answer:
The lcm is; 40b^2n^3
Step-by-step explanation:
There are no common factors between the two expressions and as such the lcm will be found by obtaining the product of he two;
8b^2*5n^3 = 40b^2n^3
