Question

8 gal to 9 1/3 gal write ratio in lowest form with whole numbers in numerator and denominator

Answer 1

Answer:

$\bold{\dfrac{6}{7}}$

Step-by-step explanation:

Given ratio is:

8 gal to $9\frac{1}3$ gal

To find:

Ratio in Lowest form with whole numbers in numerator and denominator.

Solution:

First of all, let us convert $9\frac{1}3$ to simple $\frac{p}{q}$ form:

Formula:

$a\dfrac{b}{c} = \dfrac{a\times c+b}c$

Using the formula, we get:

$9\dfrac{1}{3} = \dfrac{9\times 3+1}{3} = \dfrac{28}{3}$

Now, let us have a look at the ratio:

$8 : \dfrac{28}{3}$

Any ratio, $p:q$ can be written as $\frac{p}{q}$.

Writing given ratio as per above:

$\dfrac{8}{\dfrac{28}{3}}\\\Rightarrow \dfrac{8 \times 3}{28}\\\Rightarrow \dfrac{2\times 3}{7}\\\Rightarrow \bold{\dfrac{6}{7}}$

Therefore, the answer is

$\bold{\dfrac{6}{7}}$