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emmasim [6.3K]
3 years ago
5

A single die is rolled. Find the probability of each of the following events :

Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

\frac{1}{2} and \frac{1}{3}

There are 6 possible outcomes when rolling a die, 1, 2, 3, 4 , 5, 6

A

numbers less than 4 are 1, 2, 3

P( number less than 4 ) = \frac{3}{6} = \frac{1}{2}

B

numbers greater than 4 are 5, 6

P( number greater than 4 ) = \frac{2}{6} = \frac{1}{3}


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1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).

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4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.

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Hope this helped :) Have a great day 
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