Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
3.5 meters
Step-by-step explanation:
- 1:4 = x:14 ; where x is the unknown length of A
- 1/4 = x/14 (Cross multiply)
- Giving us, 4×x = 14×1
- 4x = 14 (Divide both sides by co-efficient of x, which is 4)
- x = 14/4
- x = 3.5
- Therefore, the length of A is 3.5 meters.
Answer: Oblique Asymptotes: y = 2 x/ e^1.5
Step-by-step explanation: Find the asymptotes
brainliest or a thank you pls <33 :)
Time taken to drive to her grandparents house = 6 5/6 hours
We convert this mixed into improper fraction, we get = 41/6 hours
Time taken to drive to her grandparents house = 41/6 hours
Time taken to drive back = 8 2/9 hours
We convert this mixed into improper fraction, we get = 74/9 hours
Time taken to drive back = 74/9 hours
Difference between the two = 74/9 - 41/6 = (148-123)/18 = 25/18 hours = 1 7/18 hours
Therefore it took 1 7/18 hours longer to drive back.
Hey! My last name's Alvarez too! Anyway, the answer came out to 180cm squared. Hope I helped! Since you can barely get more than one or two answers on this site
