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Alex
3 years ago
14

1×100,000+3×10,000+9×1,000+8×100+5×10+2×1 whats the area in standard form and word form?

Mathematics
1 answer:
nignag [31]3 years ago
3 0
Add 1 x100,000 + 3x10,000 + 9 x 1,000 +8x 100 + 5x 10+ 2x1 = 139,852. One hundred thirty nine thousand eight hundred fifty two
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Find the surface are of the composite figure.
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Answer:

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7 0
3 years ago
Which set of ordered pairs does not represent a function
Alex Ar [27]
<h3>Answer:</h3>

The Second one {(-8,-7), (4,-2), (2,9), (-8,8)}

<h3 /><h3>Step-by-step explanation:</h3>

A function only gives ONE out put for a given value. But the second set has two outputs if we input -8, it gives you -7 and 8 so this must not be a function.

6 0
3 years ago
Read 2 more answers
When planning his crops, Farmer Tim knows that his 7 acres can support peas and carrots. He wants to make $7,000 from his crops.
dsp73
This is the concept of algebra, we are required to get the equation that would be a constraint in the system of equation,
The total amount that the farmer want to make is $7000
amount he can make per acre of land is $2000, the amount he can make per acre will $1000. The variable representing peas and carrots are p and c retrospectively;
The total amount made from this can be represented by the equation below;
Total amount made by p acres of peas will be:
2000*p=$ 2000p
Total amount made by c acres of carrots:
1000*c=$1000c
Total  amount will be given by:
2000p+1000c=7000

this can be simplified by dividing through by 1000 to get:
p+c=7

The correct answer is C.
6 0
3 years ago
Read 2 more answers
Help ASAP...............
choli [55]

Answer:

This is not a question. please provide a question.

7 0
3 years ago
Use a linear approximation (or differentials) to estimate the given number.
bagirrra123 [75]
Would use the algorithm for solving square root.

For square root,  √n

x₁ = 0.5(x₀ + n/x₀)        

(This formula is known and for square root, and can be derived using Newton-Raphson's approximation equation)

Where x₀ is the initial guess.  x₁ becomes the new guess.

For √100.6  let our initial guess be 10,  x₀ = 10,  n = 100.6

Our approximation shall be to 3 decimal places. Once we get the same answer twice we stop the algorithm.

x₀ = 10,  x₁ = 0.5(x₀ + n/x₀),    x₁ = 0.5(10 + 100.6/10)  = 10.030, x₁ = 10.030

x₂ = 0.5(x₁ + n/x₁),    x = 0.5(10.030 + 100.6/10.030)  ≈10.015,  x₂ ≈ 10.030 (to 3 decimal places)

Since x₂≈ x₁, the algorithm stops.

So the √100.6 is ≈ 10.030 to 3 decimal places.

I hope this helps.
4 0
3 years ago
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