Let x = Initial Price
If we increase x by 5%, we are adding 0.05x
Therefore, the new price = x + 0.05x = 1.05x
If the ticket has increased by £2.30, £2.30 is 5% of the initial price, or 0.05x
0.05x = 2.30
x = 2.30/0.05
x = 46
Therefore, the price of the ticket before the increase was £46
You can also check this backwards by doing 46*0.05 = 2.30
56 is the answer 56 5 letter combinations
First, you have to do some factorization
60 = {1,2,3,4,5,6,10,12,15,20,30,60}
72 = {1,2,3,4,6,8,9,12,18,24,36,72}
the GCF is 12
now we find the number that you multiply by 12 to get 60 and another number to get 72.
12 x 5 = 60
12 x 6 = 72
now we notice if you add 60 + 72, we can now tell that it also equals (12)(5)+(12)(6)= 12(5+6)
Answer:
i) it is not possible for the student to receive an A in the class
ii) 119 points
iii) 84points
Step-by-step explanation:
Total exam scores = 350points
homework scores of 7, 8, 7, 5, and 8
Let the third exam score =y
Exam scores = 81, 80, x
i) To know if the student would get an A in class, we would find the third exam score
(Scores received by a student)/ (total scores) = least of the grade percentage to get an A
(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.9
(196+x)/350 = 0.9
196+x = 350 × 0.9
196+x = 315
x = 315-196
x = 119
119 > 100
Since the maximum grade for each of the exam score is 100points, it is not possible for the student to receive an A in the class.
ii) Since the least of the grade percentage that would guarantee an A is 0.9, the minimum score on the third exam that will give an A = 119points
iii) (Scores received by a student)/ (total scores) = least of the grade percentage to get a B
(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.8
(196+x)/350 = 0.8
196+x = 350 × 0.8 = 280
x = 280-196
x = 84
The minimum score on the third exam that will give a B = 84points
