
now, the angle of θ, can only have a "y" value that is positive on, well, y is positive at 1st and 2nd quadrants
and "x" is positive only in 1st and 4th quadrants
now, that angle θ, can only have those two fellows, "y" and "x" to be positive, only in the 1st quadrant, and also both to be negative on the 3rd quadrant.
and that those two fellows, can also be both negative in the 3rd quadrant
3/1 = 3, and -3/-1 = 3
so, the solutions can only be "3", when both "y" and "x" are the same sign, and that only occurs on the 1st and 3rd quadrants
I will find x, so 4x-4=180, so 4x=184, so x=46
Sorry if i answered wrong I don't understand what it is asking for.
Answer:
1/5
Step-by-step explanation:
Answer:
Look at the answers bolded below
Step-by-step explanation:
To get the reference angle, just subtract 115° from 180°
180 - 115 = 65
So the reference angle is 65°
I'm not sure how many coterminal angles you need, but to get them you could just add or subtract 360°.
For example, a positive coterminal angle could be:
115 + 360 = 475°
a negative coterminal angle could be:
115 - 360 = -245°
Hope this helped :)
Hi there! There are no numbers listed, therefore I'm unable to do answer your question. Are there numbers included in the problem?