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ValentinkaMS [17]

3 years ago

13

Suppose an ideal gas is in a container 8.0 l in volume and allowed to expand by having a piston move. The final volume after the

piston moves is 16.0 l. If the gas is originally at a pressure of 33,000 pa and a temperature of 300.0 k and the temperature is maintained, what will be the new pressure?

1 answer:

wariber [46]3 years ago

7 0

the initial condition is given as -

$p_{1}$ =33,000 pa

$v_{1}$ =8.0 litre i.e 8× $10^{-3}$ $m^{3}$

$t_{1}$ =300k

final state is given as-

$v_{2} =16 litre$ i.e16 $*10^{-3}$ $m^{3}$

$p_{2} =?$

$t_{2}$ =300k[the temperature is constant here]

here the temperature is constant.we have to calculate the final pressure

as per the Boyle's law,

$p_{1} *v_{1} =p_{2} *v_{2}$

$p_{2} =\frac{p_{1}*v_{1} }{v_{2} }$

= $\frac{8*10^{-3}*33000 }{16*10^{-3} }$

=16500 pa [ans]

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