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ANEK [815]
3 years ago
12

Which of the following statements is not correct? A every square is a parallelogram B every parallelogram is a rectangle C every

rhombus is a parallelogram D every rectangle is a parallelogram
Mathematics
1 answer:
n200080 [17]3 years ago
7 0
A. A square is a special type of parallelogram, so every square is a parallelogram. A. is true.

B. Every parallelogram has two sets of opposite sides parallel, but not all angles are right angles. Only some parallelograms are rectangles, not all. B. is false.

C. A parallelogram with 4 congruent sides is a rhombus. A rhombus is a special type of parallelogram, so every rhombus is a parallelogram. C. is true.

D. A rectangle is a special type of parallelogram, so every rectangle is a parallelogram. D. is true.
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Someone help w pre-algebra, smth about proportional data
inessss [21]

Answer:

The answer is no because for 1 hour he gets 20 dollars and for 2 hours he gets 30$ (which is less for working 2 hours). So, if you multiply 2 hours with 20 dollars, you should get 40, not 30. So therefore, it is not proportional. And same for 3 hours: multiply 3 with 20 to get 60, not 50.

6 0
2 years ago
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4000 (4x10^3) times 400 (4x10^2) is equal to 16x10^5 ( 1,600,000)
5 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So \mu = 375, \sigma = 68

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So n = 6, s = \frac{68}{\sqrt{6}} = 27.76

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 375}{27.76}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So \mu = 522, \sigma = 106

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So n = 6, s = \frac{106}{\sqrt{6}} = 43.27

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 523}{43.27}

Z = -2.61

Z = -2.61 has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0
3 years ago
From sea level, a submarine descends 20 feet per minute. Where is the submarine in relation to sea level 5 minutes after it star
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The correct answer is C.) 100 feet

(Feet per minute) x (number of minutes)

20x5 = 100
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+4a^2-9a+11
=3a^3+4a^2-a+5

</span>
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3 years ago
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