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alekssr [168]
3 years ago
15

How many pieces 3 and three fifths in. long can be cut from 28 metal rods each 15 in.​ long? Disregard waste.

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

Answer: 112 pieces


Step-by-step explanation:

1. Rewrite 3^{\frac{3}{5}} as a decimal. Divide the numerator and the denominator of the fractional part and add it to the integer part:

3+0.6=3.6in

2. You know that each metal rod is 15 inches long. Then, you must divide the lenght of each one by 3.6:

pieces=\frac{15in}{3.6in}4.16

3. The waste is 0.16, therefore, you obtain 4 pieces from a metal rod. The total pieces obtained from 28 metal rods are:

total=4pieces*28=112pieces

Cerrena [4.2K]3 years ago
3 0

<u>Answer:</u>

116 whole pieces

<u>Step-by-step explanation:</u>

We have a 28 metal rods that are 15 inches long each, out of which we need to cut 3\frac{3}{5} inches long metal rods.

Firstly, we will convert the mix fraction into improper fraction and then divide the total length of the rod by it.

3\frac{3}{5} inches = \frac{18}{5} inches

Dividing the total length of rod by this length and multiplying it by 28 to get:

\frac{15}{\frac{18}{5} } = 28 (15 * \frac{5}{18}) = 116.6

Therefore, 116 whole pieces can be cut from the given length of rod.

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