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Ede4ka [16]
3 years ago
15

Rana sells 192 cakes in the ratio small: medium: large = 7 : 6 : 11.

Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

S = £1.28

Step-by-step explanation:

Let the small, medium and large cakes be S, M and L respectively.

Given the following data;

Total profits = £532.48

Total number of cake = 192 cakes

Ratio of S:M:L = 7:6:11

Sum of ratio = 7+6+11 = 24

To find number of each cakes, we would divide the total number of cakes by the sum of ratio;

Number of each cakes = 192/24

Number of each cakes = 8

Next, we determine the exact number of each type of cakes.

Small = 7*8 = 56 cakes.

Medium = 6*8 = 48 cakes.

Large = 11*8 = 88 cakes.

For the profits;

Translating the word problem into an algebraic expression, we have;

M = 2S

L = 3S

56S + 48*(2S) + 88*(3S) = £532.48

56S + 96S + 264S = 532.48

416S = 532.48

S = 532.48/416

S = £1.28

Therefore, the profit for one small cake is £1.28

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Answer:

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-4(8r+3)

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3 years ago
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the total attendance at a concert in a theater hall was 1500, of this total 400 were children,850 were women , and the remaining
AleksandrR [38]

<u>Answer:</u>

Below!

<u>Step-by step explanation:</u>

<u>We know that:</u>

  • 400 + 850 + m = 1500

<u>Solution of Question A:</u>

<u>Percent of children: Total children/Total attendance</u>

  • => 400/1500
  • => 4/15
  • => 0.27 (Rounded to nearest hundredth)
  • => 0.27 x 100
  • => 27%

<u>Hence, the percent of children is about 27%.</u>

<u>Solution of Question B:</u>

<u>Percent of women: Total women/Total attendance</u>

  • => 850/1500
  • => 85/150
  • => 17/30
  • => 17/30 x 100
  • => 17/3 x 10
  • => 170/3
  • => 56.67%

<u>Hence, the percent of women is 56.67%.</u>

<u>Solution of Question C:</u>

  • 400 + 850 + m = 1500
  • => 1250 + m = 1500
  • => m = 1500 - 1250
  • => m = 250

<u>Percent of men: Total men/Total attendance</u>

  • => 250/1500
  • => 1/6
  • => 0.17 (Rounded to nearest hundredth)
  • => 0.17 x 100
  • => 17%

<u>Hence, the percent of men is about 17%</u>

Hoped this helped.

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2 years ago
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A is the answer because remember A is for adults and C is for Children.
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The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t
velikii [3]

Answer:

3.84% of months would have a maximum temperature of 34 degrees or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.9, \sigma = 2.31

What percentage of months would have a maximum temperature of 34 degrees or higher?

This is 1 subtracted by the pvalue of Z when X = 34. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 29.9}{2.31}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

1 - 0.9616 = 0.0384

3.84% of months would have a maximum temperature of 34 degrees or higher

8 0
3 years ago
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