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Paha777 [63]
3 years ago
15

if 5 litres of water are drawn from a cylindrical container of internal diameter 56cm find the drop in the level of water in the

container​
Mathematics
1 answer:
AlexFokin [52]3 years ago
4 0

Answer:

the drop in the level of water in the container is 2.03 cm

Step-by-step explanation:

The volume of a cylinder can be written as;

V = \pi r^2h=\frac{\pi d^2h}{4}  \\where;\\r = radius \\h = height \\d = diameter

the change in height when the volume changes can be derived by differentiating the equation.

dV =\frac{\pi d^2}{4} dh\\dh = dV\frac{4}{\pi d^2}

substituting the given values;

\left \{ {{dV=5 litres= 5000cm^3} \atop {d=56 cm}} \right.

dh = 5000\frac{4}{\pi * 56^2}\\dh = 2.03cm

the drop in the level of water in the container is 2.03 cm

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45=45

She worked 45 hours each week

 *the reason it is 2x-15 and not 15+2x is because "more than" is considered a "turn around word" meaning it is the opposite
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George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends
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Answer:

Area of Pool cover: 110.25π

Length of rope: 21π

Step-by-step explanation:

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____________________________________________________________

If ur teacher wants you to use 3.14 as pi then these are your answers:

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8 0
3 years ago
ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
3 years ago
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