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UNO [17]
2 years ago
7

Write and solve a word problem that involves dividing by 4

Mathematics
1 answer:
Gala2k [10]2 years ago
4 0
You could say 20÷4=5 or 189÷4=47.25 and another example would be 820÷4=205
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Which information is necessary to solve this problem?
prohojiy [21]
That would be  400 / 28 =  14.29 gallons to nearest hundredth
3 0
3 years ago
7. The length of a minute hand of a clock is 3.5cm. Find the angle it turns through if it
babymother [125]

Answer:

The angle it turns through if it  sweeps an area of 48 cm²   is   448.8°

Step-by-step explanation:

If the length of a minute hand of a clock is 3.5cm, to find the angle it turns through if it  sweeps an area of 48 cm, we will follow the steps below;

area of a sector = Ф/360  ×   πr²

where Ф is the angle,  r is the radius   π is a constant

from the question given, the length of the minute hand is 3.5 cm, this implies that radius r = 3.5

Ф =?   area  of the sector= 48 cm²    π = \frac{22}{7}

we can now go ahead to substitute the values into the formula  and solve Ф

area of a sector = Ф/360  ×   πr²

48   =  Ф/360  ×  \frac{22}{7} × (3.5)²

48 = Ф/360  ×  \frac{22}{7} ×12.25

48 = 269.5Ф / 2520

multiply both-side of the equation by 2520

48×2520 = 269.5Ф

120960 = 269.5Ф

divide both-side of the equation by 269.5

448.8≈Ф

Ф = 448.8°

The angle it turns through if it  sweeps an area of 48 cm²   is   448.8°

7 0
3 years ago
What is the surface area of the cylinder with height 8 mi and radius 6 mi? Round your answer to the nearest thousandth.
maksim [4K]

Answer:ANSWER would either be 120π or about 376.8

Step-by-step explanation:

A=2πrh+2πr2

A=2π*6*8+2π*6*2

A=96π+24π

A= 120π

or

A≈376.8

ANSWER would either be 120π or about 376.8

3 0
2 years ago
Read 2 more answers
Brand Number of Packets Cost
Sveta_85 [38]

Answer:

B) Brand 2

Step-by-step explanation:

Brand 1: $10.68 ÷ 12 = 0.89

Brand 2: $9.44 ÷ 16 = 0.59

Brand 3: $15.30 ÷ 18 = 0.85

Brand 4: $21.84 ÷ 24 = 0.91

Brand 5: $20.40 ÷ 30 = 0.68

Least cost per packet is of Brand 2

3 0
3 years ago
Read 2 more answers
If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
goldenfox [79]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

3 0
2 years ago
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