Answer:
10 i think
Step-by-step explanation:
The common ratio in a geometric sequence is the ratio between 2 consecutive terms:
-8/2=-4,
then the sequence is 2, -8, 32, -128, -512, 2048, ...
let
![a_n](https://tex.z-dn.net/?f=a_n)
be the nth term of the sequence, then
![a_1= 2](https://tex.z-dn.net/?f=a_1%3D%202)
![a_2=2(-4)](https://tex.z-dn.net/?f=a_2%3D2%28-4%29)
![a_3=2(-4)(-4)=2(-4)^{2}](https://tex.z-dn.net/?f=a_3%3D2%28-4%29%28-4%29%3D2%28-4%29%5E%7B2%7D%20)
![a_4=2(-4)(-4)(-4)=2(-4)^{3}](https://tex.z-dn.net/?f=a_4%3D2%28-4%29%28-4%29%28-4%29%3D2%28-4%29%5E%7B3%7D%20)
.
.
.
so clearly
![a_n=2(-4)^{n-1}](https://tex.z-dn.net/?f=a_n%3D2%28-4%29%5E%7Bn-1%7D%20)
and, clearly n are integers >0, since we have a 1st term, a second term and so on... of a sequence (we do not have a "zero'th term"!
Answer:
<span>C. an=2(-4)^n-1; all integers where n>0</span>
Original:350 discount:87.50 off new price: 262.5
Answer:
69
Step-by-step explanation:
it's the holy number jesus christ can confirm
Answer:
Step-by-step explanation:
here you go!!