The sum of two numbers is eleven. One number is thirty-eight less than six times the other. Find the numbers.
1 answer:
Answer:
One of the number is 4 while the other is 7
Step-by-step explanation:
The sum of two numbers is eleven
Let the numbers be x and y
X+ y = 11
One number is thirty-eight less than six times the other
X= 6y-38
X+ y = 11
6y-38 +y= 11
6y+y= 11+38
7y=49
Y= 49/7
Y= 7
X+ y = 11
X+7= 11
X= 11-7
X= 4
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Answer: The answer would be choice C because there is a constant rate of change of 3 :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given that:
And we want to find F'(0).
First, find F(x):
![\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20f%283x%29%5D)
From the chain rule:
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Then:
In conclusion, F'(0) = 15.
Answer:
-1
Step-by-step explanation:
Answer:
Inverse of g(x)=x+15/3
Step-by-step explanation:
g(x)=3x-15
Let, g(x) be y
y=3x-15
Interchange x and y
x=3y-15
x+15=3y
y=x+15/3
Then answer should be w = 4/3 if that’s what you lookin for
