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3 years ago

Evaluate the following expression (a + b)^0

Mathematics

2 answers:

ira [324]3 years ago

8 0

Answer:

the answer is 1

elixir [45]3 years ago

3 0

Answer:

So, $(a + b)^0=1$

Step-by-step explanation:

$(a + b)^0$

To evaluete this expression we apply exponential property

$x^0=1$

IF any expression has exponent 0 then the value is 1 always

for example, $3^0 =1$

$5^0=1$

$(x+2)^0=1$ because exponent is 0

So, $(a + b)^0=1$

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Step-by-step explanation:

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Why is -a² is always negative (a ≠ 0) and why is (-a)² is always positive?

hjlf

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